2 in

If you rent a car for one day and drive 225 miles, the cost is $80. If you drive 350 miles in one day, the cost is $105. Let cm)

kolezko [41]

Answer:

a) $(x_1 = 225, y_1 = 80) , (x_2 = 350, y_2 = 105)$

And we want to find a function:

$C (m) = b_1 m + b_0$

We can find the slope with this formula:

$b_1= \frac{105-80}{350-225}= \frac{25}{125}=0.2$

And then we can use the point $(x_1 = 225, y_1 = 80)$ to find the intercept $b_o$ and we got:

$80 = 0.2*225 +b_0$

$b_0 = 80-45 = 35$

So then the linear function is given by:

$C(m) = 0.2 m + 35$

b) For this case we have that m = 475 so we can replace into the function to find the cost like this:

$C(m =475) = 0.2*475 + 35 = 130$

And for the other case we have a cost of 155 and we want to find the number of miles associated so we can do this:

$155 = 0.2m + 35$

$155-35= 120 = 0.2 m$

$m= \frac{120}{0.2}= 600 mi$

Step-by-step explanation:

For this case we can define the following notation:

m= represent the miles travelled

C= represent the cost

Part a

For this case we have the following two points given:

$(x_1 = 225, y_1 = 80) , (x_2 = 350, y_2 = 105)$

And we want to find a function:

$C (m) = b_1 m + b_0$

We can find the slope with this formula:

$b_1= \frac{105-80}{350-225}= \frac{25}{125}=0.2$

And then we can use the point $(x_1 = 225, y_1 = 80)$ to find the intercept $b_o$ and we got:

$80 = 0.2*225 +b_0$

$b_0 = 80-45 = 35$

So then the linear function is given by:

$C(m) = 0.2 m + 35$

Part b

For this case we have that m = 475 so we can replace into the function to find the cost like this:

$C(m =475) = 0.2*475 + 35 = 130$

And for the other case we have a cost of 155 and we want to find the number of miles associated so we can do this:

$155 = 0.2m + 35$

$155-35= 120 = 0.2 m$

$m= \frac{120}{0.2}= 600 mi$

6 0

3 years ago

A pole that is 3.5m tall casts a shadow that is 1.47m long. At the same time, a nearby tower casts a shadow that is 42.75m long.

Stells [14]

Answer:

The height of the tower nearby the pole is 102 m.

Solution:

Given,

Height of the pole = 3.5 m

Length of the shadow of the pole = 1.47 m

Length of the shadow of the tower nearby = 42.75 m

Let us assume the height of the tower as x

$\frac{height of the pole}{length of the shadow of the pole}=\frac{height of the tower}{length of the shadow of the tower}$

$\frac{3.5}{1.47} = \frac{x}{42.75}$

On solving for x we get,

$x = \frac{3.5}{1.47}\times 42.75$

$x = 101.785 m$

On rounding off to the nearest meter we get,

x=102 m

$\therefore$ The height of the tower is 102 meter.

7 0

3 years ago

Part C

Kay [80]

From the inscribed circle, AE and AD are the radius of the circle while BE and BD are the tangents.

<h3>What is an inscribed circle?</h3>

An inscribed circle simply means the largest circle that's contained in a triangle.

An inscribed circle touches its tangent to the three sides. In this case, AE and AD are the radius of the circle while BE and BD are the tangents. Also, angle ABE and ABD are 60°.

Learn more about inscribed circle on:

brainly.com/question/12199537

8 0

2 years ago

Are the numbers linear or nonlinear x- 0, 3, 6, and 9 y- -3, 9, 21, and 33

fenix001 [56]

Answer:

I'm not really,

sure but I think non linear

Step-by-step explanation:

sorry if I'm wrong

4 0

3 years ago

Read 2 more answers

Combine like terms in the expression below. 5c + 6 + 8c - 2 Plz help

Eva8 [605]

Answer:
13c+6-2

Explanation:
You combine the amount of cs with each other.

8 0

3 years ago