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german
3 years ago
13

What is the standard form of (2-4i)(3+51)/(3+i)

Mathematics
1 answer:
garri49 [273]3 years ago
6 0
<span><span><span><span><span><span><span><span><span><span><span><span>(</span></span><span><span><span><span><span><span>1</span></span><span><span>⋅</span></span><span><span>3</span></span></span><span><span>+</span></span><span><span><span>1</span></span><span><span><span>(</span></span><span><span><span><span>5</span></span><span><span>i</span></span></span></span><span><span>)</span></span></span></span></span><span><span><span><span><span>−</span></span><span><span>2</span></span></span><span><span>i</span></span></span><span><span><span>(</span></span><span><span><span><span>3</span></span><span><span>+</span></span><span><span><span>5</span></span><span><span>i</span></span></span></span></span><span><span>)</span></span></span></span></span></span><span><span>)</span></span></span><span><span><span>(</span></span><span><span><span><span>3</span></span><span><span><span>−</span></span><span><span>i</span></span></span></span></span><span><span>)</span></span></span></span></span></span><span><span><span><span>5</span></span></span></span><span /></span><span /></span></span></span></span></span><span>1⋅3+15i-2i3+5i3-i5</span>
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Solve x+2/x-4&lt;0<br><br> A)–4 &lt; x &lt; –2<br> B)–2 &lt; x &lt; 4<br> C)–2 &lt; x &lt; –4
Gelneren [198K]

Domain:\ x\neq-2\\\\\dfrac{x+2}{x-4}

Other method:

\dfrac{x+2}{x-4}

zeros of numerator and denominator are x = -2 and x = 4.

Look at the second picture.

for x < -2 → x + 2 < 0 and x - 4 < 0

therefore \dfrac{x + 2}{x - 4}=\dfrac{(-)}{(-)}>0

for -2 < x < 4 → x + 2 > 0 and x - 4 < 0

therefore \dfrac{x+2}{x-4}=\dfrac{(+)}{(-)} < 0

for x > 4 → x + 2 > 0 and x - 4 > 0

therefore \dfrac{x+2}{x-4}=\dfrac{(+)}{(+)} > 0

<h3>Answer: B) -2 < x < 4</h3>

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18 {x}^{2}  - 50 \\  = 2(9 {x}^{2}  - 25) \\  = 2(3x - 5)(3x + 5)

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