Because you are using the format y = mx +c the c value is the y offset.
in this equation the equation can be rewritten as y = 1x -3
Thus the y intercept, the y offset, must be -3.
Hope this helps! :)
To get that number in the problem, you need to translate first the word problem into mathematical expression.
We will let x as the number.
six more than the product of a number and -2 is greater than 10 can be written as (-2x) + 6 > 10
We will now solve for x to get the number.
(-2x) + 6 > 10
Add -6 to both sides of the equation
-2x + 6 - 6 > 10 - 6
-2x > 4
Divide both sides of the equation with -2
Take note that if we divide a negative number in inequality, the inequality symbol will be change from greater than to less or from less than to greater than.
-2x / -2< 4 / -2
x < -2
Therefore, the number that we are looking for is less than -2.
Answer:
Width = 9
Step-by-step explanation:
(P=2L+2W) = 72
L = 3W<- length is triple the width
(P = 2(3W) + 2W) = 72
P = 8W =72
W = 9
Answer: Bridget was thinking of the number 2.95
Step-by-step explanation:
21.9 / 2 = 10.95
10.95 - 8 = 2.95
Answer:
1. 1340
2. Variance = 47200, standard deviation = 217.25556
Step-by-step explanation:
1-
If X is the random variable that give the number of admissions, then the expected number of admissions<em> E[X]</em> for the fall semester is
1080*P(X=1080)+1380*P(X=1380)+1540*P(X=1540) =
1080*0.4+1380*0.1+1540*0.5 = 1340
2-
The <em>variance</em> is defined as
![\sigma^2=E[X^2]-(E[X])^2}](https://tex.z-dn.net/?f=%5Csigma%5E2%3DE%5BX%5E2%5D-%28E%5BX%5D%29%5E2%7D)
We have
![E[X^2]=(1080)^2*0.4+(1380)^2*0.1+(1540)^2*0.5=1842800](https://tex.z-dn.net/?f=E%5BX%5E2%5D%3D%281080%29%5E2%2A0.4%2B%281380%29%5E2%2A0.1%2B%281540%29%5E2%2A0.5%3D1842800)
whereas
![(E[X])^2=(1340)^2=1795600](https://tex.z-dn.net/?f=%28E%5BX%5D%29%5E2%3D%281340%29%5E2%3D1795600)
So the variance equals
The <em>standard deviation is just the square root of the variance</em>, so, the standard deviation is
