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3 years ago

Miast

1 answer:

6 0

Answer: All options are correct (assuming that option A is in the form of Y=5). Typing error in the question. But I will clear your concepts on that.

Step-by-step explanation:

Equation of the form (y = c) are the horizontal lines that are passing through the y-intercept 'c' or cutting/passing through the y-axis at 'c'.

All equations in the option are of the form y = c

option A , (y=5)

option B , (y=1)

option C , (y=1)

option D, (y=5)

All are parallel to X-axis.

For an equation to be parallel to y-axis should have the form x = a (Vertical line passing through x-intercept 'a')

#Muhib

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In a pizza takeout restaurant, the following probability distribution was obtained for the number of toppings ordered on a large

Elis [28]

Answer:

The random variable (number of toppings ordered on a large pizza) has a mean of 1.14 and a standard deviation of 1.04.

Step-by-step explanation:

The question is incomplete:

The probability distribution is:

x P(x)

0 0.30

1 0.40

2 0.20

3 0.06

4 0.04

The mean can be calculated as:

$M=\sum p_iX_i=0.3\cdot 0+0.4\cdot 1+0.2\cdot 2+0.06\cdot 3+0.04\cdot 4\\\\M=0+0.4+0.4+0.18+0.16\\\\M=1.14$

(pi is the probability of each class, Xi is the number of topping in each class)

The standard deviation is calculated as:

$s=\sqrt{\sum p_i(X_i-M)^2}\\\\s=\sqrt{0.3(0-1.14)^2+0.4(1-1.14)^2+0.2(2-1.14)^2+0.06(3-1.14)^2+0.04(4-1.14)^2}\\\\s=\sqrt{0.3(-1.14)^2+0.4(-0.14)^2+0.2(0.86)^2+0.06(1.86)^2+0.04(2.86)^2}\\\\ s=\sqrt{0.3(1.2996)+0.4(0.0196)+0.2(0.7396)+0.06(3.4596)+0.04(8.1796)}\\\\s=\sqrt{0.3899+0.0078+0.1479+0.2076+0.3272}\\\\ s=\sqrt{ 1.0804 }\\\\s\approx 1.04$

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3 years ago

John has 8/9 of a gallon of apple cider vinegar. If it takes 1/7 of a gallon of vinegar to make a batch of collard greens, how m

kumpel [21]

1/7 gallon = 1 batch

[multiply by 7 through]
1 gallon = 7 batches

[multiply by 8/9 through]
8/9 gallon = 7 x 8/9
8/9 gallon = 6 2/9

[Good enough to make 6 batches, not enough to make 7 batches]

So he can make 6 batches of collard green

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3 years ago

How many times greater is the value of 4 in 547 than the value of the 4 and 84

sesenic [268]

Answer:

Step-by-step explanation:

How many times greater is the value of 4 in 547 than the value of the 4 and 84?

547: 500 + 40 + 7

5 is in the hundreds place

4 is in the tens place

7 is in the ones place

84: 80 + 4

8 is in the tens place

4 is in the ones place

The value of 4 in 547 is 10 times greater than the value of 4 in 84.

Since the 4 in 547 is in the tens place, while the 4 in 84 is in the ones place.

Also, 4 * 10 = 40

Hope this helps!

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The answer is 2 I believe

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Natali [406]

the greatest common factor (GCF) of 12, 24, and 48 is 12.

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