Answer:
we need more
Step-by-step explanation:
Answer:
Proved
Step-by-step explanation:
To prove that every point in the open interval (0,1) is an interior point of S
This we can prove by contradiction method.
Let, if possible c be a point in the interval which is not an interior point.
Then c has a neighbourhood which contains atleast one point not in (0,1)
Let d be the point which is in neighbourhood of c but not in S(0,1)
Then the points between c and d would be either in (0,1) or not in (0,1)
If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.
Then we find that dn is a boundary point of S
But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.
Every point of S=(0, 1) is an interior point of S.
Answer:
30, 9, 15, 29
Step-by-step explanation:
Triangle 1, yellow
Triangle 2, blue
Triangle 3, green
Triangle 4, red
Ok, use the sum of triangle theorm all angles of the triangle has a sum of 180 degrees. B is 90 degrees because it labeled it self ABC the A angle seems by the degree to be at the top of the triangle and there needs to be a 90 degree angle in a right triangle. Now if you add 90 + 28 you get 118 degrees subtract that from the sum of all the angles ( 180 degrees), and get 62 degrees as angle C. Angle A is 28 degrees, angle B is 90 degrees, angle C is 62 degrees.
