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a_sh-v [17]
3 years ago
5

1. Fifty-six percent of what is 23? What proportion would you write to solve this problem?

Mathematics
1 answer:
Brums [2.3K]3 years ago
6 0

Answer:

41.07

Step-by-step explanation:

1) lets use the formula, (%/100)=is/of

so:

is=23

of=x

%=56

\frac{56}{100} =\frac{23}{x}

cross multiply

56x=2300

x=41.07

so the proportions I would use are:

56/100 and 23/x

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Which of these statements is correct?
tatuchka [14]

Answer:

The system of linear equations 8x - 3y = 10 and 16x - 6y = 22 has no solution is correct.

Step-by-step explanation:

<em>1) The system of linear equations 6x - 5y = 8 and 12x - 10y = 16 has no solution.</em>

<em>Solve these linear equations simultaneously</em>

<em>Step 1 : Find y in terms of x from any one equation</em>

6x - 5y = 8

y = <u>8 - 6x</u>

        -5

<em>Step 2 : Substitute y in terms of x from step 1 in the second equation.</em>

16x - 6y = 22

16x - 6 (<u>8 - 6x)</u> = 22

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80x - 48 + 36x = 22 x -5

94x = 43

x = 0.457

<em>This statement is incorrect as it does have a solution.</em>

<em>2) The system of linear equations 7x + 2y = 6 and 14x + 4y = 16 has an infinite number of solutions.</em>

<em>Solve these linear equations simultaneously</em>

<em>Step 1 : Find y in terms of x from any one equation</em>

7x + 2y = 6

y = <u>6 - 7x</u>

        2

<em>Step 2 : Substitute y in terms of x from step 1 in the second equation.</em>

14x + 4y = 16

14x + 4(<u>6 - 7x)</u> = 16

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14x + 12 - 14x = 16

0 ≠ 4

<em>This statement is not true as there are no solutions.</em>

<em>3) The system of linear equations 8x - 3y = 10 and 16x - 6y = 22 has no solution.</em>

<em>Solve these linear equations simultaneously</em>

<em>Step 1 : Find x in terms of y from any one equation</em>

8x - 3y = 10

x = <u>10 + 3y</u>

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<em>Step 2 : Substitute x in terms of y from step 1 in the second equation.</em>

16x - 6y = 22

16(<u>10 + 3y)</u> - 6y = 22

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20 + 6y - 6y = 2

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<em>This statement is true because there are no solutions</em>

<em>4) The system of linear equations 9x + 6y = 14 and 18x + 12y = 26 has an infinite number of solutions.</em>

<em>Solve these linear equations simultaneously</em>

<em>Step 1 : Find x in terms of y from any one equation</em>

9x + 6y = 14

x = <u>14 - 6y</u>

        9

<em>Step 2 : Substitute x in terms of y from step 1 in the second equation.</em>

18x + 12y = 26

18 (<u>14 - 6y)</u> + 12y = 26

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<em>!!</em>

8 0
3 years ago
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Estimate to find the quotient if 823 divided by 23​
ivanzaharov [21]

Answer:

Step-by-step explanation:

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I need help with #1 of this problem. It has writings on it because I just looked up the answer because I’m confused but I want t
belka [17]

In the figure below

1) Using the theorem of similar triangles (ΔBXY and ΔBAC),

\frac{BX}{BA}=\frac{BY}{BC}=\frac{XY}{AC}

Where

\begin{gathered} BX=4 \\ BA=5 \\ BY=6 \\ BC\text{ = x} \end{gathered}

Thus,

\begin{gathered} \frac{4}{5}=\frac{6}{x} \\ \text{cross}-\text{multiply} \\ 4\times x=6\times5 \\ 4x=30 \\ \text{divide both sides by the coefficient of x, which is 4} \\ \text{thus,} \\ \frac{4x}{4}=\frac{30}{4} \\ x=7.5 \end{gathered}

thus, BC = 7.5

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In the above diagram,

\begin{gathered} BC=BY+YC \\ \Rightarrow BC=15\text{ + y} \end{gathered}

Thus, from the theorem of similar triangles,

\begin{gathered} \frac{BX}{BA}=\frac{BY}{BC}=\frac{XY}{AC} \\ \frac{9}{15}=\frac{15}{15+y} \end{gathered}

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\begin{gathered} \frac{9}{15}=\frac{15}{15+y} \\ \text{cross}-\text{multiply} \\ 9(15+y)=15(15) \\ \text{open brackets} \\ 135+9y=225 \\ \text{collect like terms} \\ 9y\text{ = 225}-135 \\ 9y=90 \\ \text{divide both sides by the coefficient of y, which is 9} \\ \text{thus,} \\ \frac{9y}{9}=\frac{90}{9} \\ \Rightarrow y=10 \end{gathered}

thus, YC = 10.

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1 year ago
a metal strip is being installed around a workbench that is 6 feet long and 2 feet wide. find how much stripping is needed
Stolb23 [73]
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