Question

The vertex of a quadratic function is (6, 2), and the y-intercept of the function is (0, −70). The equation of the function in vertex form, f(x)=a(x−h)2+k, is shown.−70=a(0−6) squared+2

Answer 1

Answer:

The equation of the function in vertex form is represented by $y = -2\cdot (x-6)^{2}+2$.

Step-by-step explanation:

Let $(h,k) = (6,2)$ and $(x,y) = (0, - 70)$, now we substitute on the equation of the quadratic function and solve for $a$:

$y = a\cdot (x-h)^{2}+k$

$-70 = a\cdot (0-6)^{2}+2$

$-70 = 36\cdot a + 2$

$36\cdot a = -72$

$a = -2$

Therefore, the equation of the function in vertex form is represented by $y = -2\cdot (x-6)^{2}+2$.

Answer 2

Answer:

THE ANSEWR IS BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB

Step-by-step explanation:

b the seconed option