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3 years ago

40 points!! What is the area of the quadrilateral with vertices at (2, -4), (4, -4), (2, 1), and (4, 1)?

Mathematics

1 answer:

stiv31 [10]3 years ago

8 0

Answer:Expand areaofthequadrilateralwithverticesat(2, - 4),(4, - 4),(2,1),and(4,1)

Step 1: Multiply (areaofthequadrilateralwithverticesat) * (2, - 4,)

Step 1.1: Multiply areaofthequadrilateralwithverticesat by each term in 2, - 4,

Step 1.1.1: Multiply areaofthequadrilateralwithverticesat * 2,

Group constants and powers by variable

(1 * 1)(a1 + 1 + 1 + 1 + 1 + 1r1 + 1 + 1 + 1e1 + 1 + 1 + 1 + 1o1f1t1 + 1 + 1 + 1 + 1h1 + 1q1u1d1i1 + 1 + 1l1 + 1w1v1c1s1)

a6r4e5oft5h2qudi3l2wvcs

Step 1.1.2: Multiply areaofthequadrilateralwithverticesat * -4,

Group constants and powers by variable

(1 * 1)(a1 + 1 + 1 + 1 + 1 + 1r1 + 1 + 1 + 1e1 + 1 + 1 + 1 + 1o1f1t1 + 1 + 1 + 1 + 1h1 + 1q1u1d1i1 + 1 + 1l1 + 1w1v1c1s1)

a6r4e5oft5h2qudi3l2wvcs

Step 1 answer = a6r4e5oft5h2qudi3l2wvcs + 1a6r4e5oft5h2qudi3l2wvcs

Group all like terms

2a6r4e5oft5h2qudi3l2wvcs

Step-by-step explanation:

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<h3>Answer: 43 km per hour</h3>

==================================================

Work Shown:

total distance = 43+40+46 = 129 km

total time = 1+1+1 = 3 hours

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average speed = (129 km)/(3 hrs)

average speed = (129/3) (km/hr)

average speed = 43 km per hour

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$\huge\text{$k=\boxed{117}$}$

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