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Citrus2011 [14]
3 years ago
9

HELP THIS IS DUE IN 2 DAYS PLS (the question in this attachment)

Physics
2 answers:
padilas [110]3 years ago
6 0

Answer:

vengansa fresca

Explanation:

Over [174]3 years ago
3 0
Can you at least explain
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The barrel of a rifle has a length of 0.89 m. A bullet leaves the muzzle of a rifle with a speed of 620 m/s. What is the acceler
guapka [62]

Answer:

215955.06 m/s^2

Explanation:

length of barrel, s = 0.89 m

initial velocity of the bullet, u = 0 m/s

Final velocity of the bullet, v = 620 m/s

Let a be the acceleration of the bullet in the barrel

Use third equation of motion, we get

v^{2}=u^{2}+ 2as

620^{2}=0^{2}+ 2\times a \times 0.89

a = 215955.06 m/s^2

Thus, the acceleration of the bullet inside the barrel is  215955.06 m/s^2.

6 0
3 years ago
The brakes exert a 1,951 N force on a car weighing 18,985 N and moving at 12 m/s. The car finally stops. How long (in seconds) d
nata0808 [166]

Answer:20,000

Explanation:

7 0
4 years ago
The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0. 10. The mass of the object
lilavasa [31]

The force of friction is 78.4 N

What is force of friction?

Frictional force is the force created when two surfaces come into contact and slide against each other. it is given by the equation:

F_{f} = μ * F_{n}

where,

F_{f} = force of friction

μ = coefficient of friction

F_{n} = normal force

Given,

μ = 0.10,  m = 8.0 kg

We know,

F_{n} = mg

F_{n} = 8.0 * 9.8\\\\ F_{n} = 78.4 N

Subsituing the values in equation:

F_{f} = μ * F_{n}

F_{f} = 0.10 * 78.4 \\\\F_{f} = 7.84 N

The force of friction is 78.4 N.

To know more about force of friction, check out:

brainly.com/question/24386803

#SPJ4

4 0
1 year ago
Who has ideas for a prank
Nimfa-mama [501]

Answer:Probably water ballons,Paint,Etc

Explanation:

3 0
3 years ago
Read 2 more answers
is dimensionally correct relation necessarily to be a correct physical relation? explain with example.​
Andreas93 [3]

Answer: hope it helps you...❤❤❤❤

Explanation: If your values have dimensions like time, length, temperature, etc, then if the dimensions are not the same then the values are not the same. So a “dimensionally wrong equation” is always false and cannot represent a correct physical relation.

No, not necessarily.

For instance, Newton’s 2nd law is  F=p˙ , or the sum of the applied forces on a body is equal to its time rate of change of its momentum. This is dimensionally correct, and a correct physical relation. It’s fine.

But take a look at this (incorrect) equation for the force of gravity:

F=−G(m+M)Mm√|r|3r  

It has all the nice properties you’d expect: It’s dimensionally correct (assuming the standard traditional value for  G ), it’s attractive, it’s symmetric in the masses, it’s inverse-square, etc. But it doesn’t correspond to a real, physical force.

It’s a counter-example to the claim that a dimensionally correct equation is necessarily a correct physical relation.

A simpler counter example is  1=2 . It is stating the equality of two dimensionless numbers. It is trivially dimensionally correct. But it is false.

4 0
4 years ago
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