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3 years ago

Verify that the given segments are parallel.

Mathematics

1 answer:

AlekseyPX3 years ago

4 0

Answer:

Step-by-step explanation:

M and N and QR

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What is the constant rate of 2 mi and 35 minutes

Yuliya22 [10]

Answer:

<h3>0.057 miles per minute</h3>

Step-by-step explanation:

2 miles and 35 minutes

= 2 miles / 35 minutes

= 0.057 miles per minute

6 0

3 years ago

Can someone help me with this math homework please!

Ghella [55]

Answer:

$y=\frac{5}{2} \:x$

Step-by-step explanation:

A line with the highest absolute value of slope has the steepest graph

from the option, the highest is 5/2 so, y = 5/2 x is your answer.

OAmalOHopeO

3 0

2 years ago

Read 2 more answers

What is the value of c in the equation?

yuradex [85]

Answer:

the value of c = 32.13

Step-by-step explanation:

all you had to do was take one of the options and divide it by 2.1 and you'll know you have to right answer when it equals 15.3 but just remember if you are dividing by a smaller number the numerator has to be a bigger number to be able to equal whatever is on the other side of the equals symbol.

sorry I'm bad at explaining but I hope this helps

3 0

3 years ago

Read 2 more answers

1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.

xxTIMURxx [149]

First, rewrite the equation so that y is a function of x :

$x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}$

(If you were to plot the actual curve, you would have both $y=x^{2/3}$ and $y=-x^{2/3}$ , but one curve is a reflection of the other, so the arc length for 1 ≤ x ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

$\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx$

We have

$y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}$

Then in the integral,

$\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx$

Substitute

$u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx$

This transforms the integral to

$\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du$

and computing it is trivial:

$\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)$

We can simplify this further to

$\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}$

7 0

3 years ago

Can someone help me with this problem? <img src="https://tex.z-dn.net/?f=%2818x%5E2%2B9x-7%29%2F3x" id="TexFormula1" title="

Fantom [35]

I hope this helps you

5 0

3 years ago