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Bas_tet [7]
3 years ago
9

What power has the value of 27

Mathematics
2 answers:
jarptica [38.1K]3 years ago
7 0

Step-by-step explanation:

Answer:

C.3^3

sana makatulong

Ann [662]3 years ago
6 0

Answer:

option c.

c).3^3

.........................

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PLZ HELP!!! 20 POINTS!!!
dangina [55]

Answer: \\ Since \:  \widehat{SRT} = \widehat{STR} \:  \\and \:  \widehat{RTU} = \widehat{STR} + \widehat{STU} = 180^{\circ}  \\ \Rightarrow  \widehat{SRT} + \widehat{STU} = 180^{\circ} \\ \Leftrightarrow 4x - 20 + 6x = 180 \\ \Leftrightarrow10x = 200 \\ \Leftrightarrow x = 20 \\ \widehat{SRT} = 4 \times 20 - 20 = 60^{\circ}

4 0
3 years ago
Let X denote the length of human pregnancies from conception to birth, where X has a normal distribution with mean of 264 days a
Kaylis [27]

Answer:

Step-by-step explanation:

Hello!

X: length of human pregnancies from conception to birth.

X~N(μ;σ²)

μ= 264 day

σ= 16 day

If the variable of interest has a normal distribution, it's the sample mean, that it is also a variable on its own, has a normal distribution with parameters:

X[bar] ~N(μ;σ²/n)

When calculating a probability of a value of "X" happening it corresponds to use the standard normal: Z= (X[bar]-μ)/σ

When calculating the probability of the sample mean taking a given value, the variance is divided by the sample size. The standard normal distribution to use is Z= (X[bar]-μ)/(σ/√n)

a. You need to calculate the probability that the sample mean will be less than 260 for a random sample of 15 women.

P(X[bar]<260)= P(Z<(260-264)/(16/√15))= P(Z<-0.97)= 0.16602

b. P(X[bar]>b)= 0.05

You need to find the value of X[bar] that has above it 5% of the distribution and 95% below.

P(X[bar]≤b)= 0.95

P(Z≤(b-μ)/(σ/√n))= 0.95

The value of Z that accumulates 0.95 of probability is Z= 1.648

Now we reverse the standardization to reach the value of pregnancy length:

1.648= (b-264)/(16/√15)

1.648*(16/√15)= b-264

b= [1.648*(16/√15)]+264

b= 270.81 days

c. Now the sample taken is of 7 women and you need to calculate the probability of the sample mean of the length of pregnancy lies between 1800 and 1900 days.

Symbolically:

P(1800≤X[bar]≤1900) = P(X[bar]≤1900) - P(X[bar]≤1800)

P(Z≤(1900-264)/(16/√7)) - P(Z≤(1800-264)/(16/√7))

P(Z≤270.53) - P(Z≤253.99)= 1 - 1 = 0

d. P(X[bar]>270)= 0.1151

P(Z>(270-264)/(16/√n))= 0.1151

P(Z≤(270-264)/(16/√n))= 1 - 0.1151

P(Z≤6/(16/√n))= 0.8849

With the information of the cumulated probability you can reach the value of Z and clear the sample size needed:

P(Z≤1.200)= 0.8849

Z= \frac{X[bar]-Mu}{Sigma/\sqrt{n} }

Z*(Sigma/\sqrt{n} )= (X[bar]-Mu)

(Sigma/\sqrt{n} )= \frac{(X[bar]-Mu)}{Z}

Sigma= \frac{(X[bar]-Mu)}{Z}*\sqrt{n}

Sigma*(\frac{Z}{(X[bar]-Mu)})= \sqrt{n}

n = (Sigma*(\frac{Z}{(X[bar]-Mu)}))^2

n = (16*(\frac{1.2}{(270-264)}))^2

n= 10.24 ≅ 11 pregnant women.

I hope it helps!

6 0
3 years ago
WILL EARN BRAINLIEST! [Rate of Functions]
AURORKA [14]

Answer:

every pair is being multi by the next number

Step-by-step explanation:

2 x 3 =6

3 x 4 = 12 so the second number goes up one every time

7 0
3 years ago
What solid figure has 5 faces, 5 vertices, 8edges?
tekilochka [14]
Your answer is a Square Pyramid.

(Hope I helped :C

7 0
3 years ago
Read 2 more answers
What is the surface area of the prism?
Harman [31]
Area of lower rect + area of upper + 4 * sides rect areas

lower = upper rect

2 * rect1 + 4 * rect2

Area = 2 * 6 * 11 + 2 * 11 * 9 + 2 * 9 * 6 = 438 ft^2

or simply just take 2 ( and multiply each two sides.

5 0
3 years ago
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