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timofeeve [1]
3 years ago
10

Solve the following equations: 4 1/5 ÷ 1 1/5 = 11 - 1 7/18x

Mathematics
2 answers:
Savatey [412]3 years ago
7 0

Answer: what kind of equations is that, that is mad hard

MAVERICK [17]3 years ago
7 0
Hope this helps you Broo

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Find the zeros of the function f(x) = (x + 2)(x - 3)(x + 12)
ser-zykov [4K]

Step-by-step explanation:

f(x) = (x + 2)(x - 3)(x + 12) = 0

(x + 2)(x - 3)(x + 12) = 0

so, the zeros of the function :

=> x1 = -2

=> x2= 3

=> x3 = -12

4 0
3 years ago
3x2 + 5x - 7(x2 + 4)
goldenfox [79]

Answer:

-4x^2+5x-28

Step-by-step explanation:

Expand -7(x^2 +4) = 3x^2+5x-7x^2-28

Simplify 3x^2+5x-7x^2-28 = -4x^2+5x-28

5 0
3 years ago
Read 2 more answers
Doug entered a canoe race. He rowed 31/2 miles in 1/2 hour. What is his average speed in miles per hour
Cloud [144]
He rowed 31.5 miles in half of an hour, to get speed per hour, you  multiply by two.
31.5*2=63
Doug's average speed is 63 miles per hour~_~
6 0
3 years ago
Find an equation (in term of x) of line through the points (-1,3) and (1,4)
Serjik [45]
ANSWER

The equation is
2y - x = 7


EXPLANATION

The equation of the line that passes through the point (-1,3) and (1,4) can be found using the formula,

y-y_1=m(x-x_1)

where

m =  \frac{4 - 3}{1  -  - 1}

m =  \frac{1}{2}
is the slope and

(x_1,y_1)
is a point on the line.



The equation of the line becomes,


y - 4 =  \frac{1}{2} (x - 1)


Multiply through by 2 to get,.

2y - 8 = x - 1

Or

2y - x = 7
4 0
3 years ago
The rate of change (dP/dt), of the number of people on an ocean beach is modeled by a logistic differential equation. The maximu
Kazeer [188]

Answer:

\frac{dP}{dt} = 2.4P(1 - \frac{P}{1200})

Step-by-step explanation:

The logistic differential equation is as follows:

\frac{dP}{dt} = rP(1 - \frac{P}{K})

In this problem, we have that:

K = 1200, which is the carring capacity of the population, that is, the maximum number of people allowed on the beach.

At 10 A.M., the number of people on the beach is 200 and is increasing at the rate of 400 per hour.

This means that \frac{dP}{dt} = 400 when P = 200. With this, we can find r, that is, the growth rate,

So

\frac{dP}{dt} = rP(1 - \frac{P}{K})

400 = 200r(1 - \frac{200}{1200})

166.67r = 400

r = 2.4

So the differential equation is:

\frac{dP}{dt} = rP(1 - \frac{P}{K})

\frac{dP}{dt} = 2.4P(1 - \frac{P}{1200})

3 0
3 years ago
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