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3 years ago

9

A rectangular garage is 15 yards long and 5 yards wide. It costs $2.00 per square yard to put in a new concrete floor. How much

would it cost to put a new concrete floor in the garage?

1 answer:

pantera1 [17]3 years ago

4 0

Say you have a box and theres one fifteen on two sides and one five on the other two side 15+15=30 and 5+5=10 and 30+10=40 and 40x2=80
Answer:$80

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Can someone help me please ?

Alex Ar [27]

Answer:

V= 40.9

Step-by-step explanation:

the top and the bottom side both equal 26.2, if you multiply that number by 2 (Because 2 sides have that same number) you get 52.4. The next step is to take the total perimeter which is 134.2, and subtract 52.4 which brings you to 81.8. Then you divide 81.8 by 2 to get your final answer of 40.9, which is the value of V. Hope this helps!

6 0

3 years ago

A dog weighs 0.5 pound when.it is born.

Mrac [35]

Answer: 0.5 to 35

Step-by-step explanation:

4 0

3 years ago

Elanso [62]

Answer:

a $A = 30 + 0.45 n$

b $A = 90.3$

c 0 customers

Step-by-step explanation:

Given

$Base\ Amount = 30$

$Rate = 0.45$ per customer

Solving (a): Amount (A) on n customers

This is calculated as:

$A = Base\ Amount + Rate * n$

$A = 30 + 0.45 * n$

$A = 30 + 0.45 n$

Solving (b): Amount on 134 customers

In this case: n = 134

So:

$A = 30 + 0.45 * 134$

$A = 30 + 60.3$

$A = 90.3$

Solving (c): Customers at noon.

At noon, the amount is 30.

So:

$A = 30 + 0.45 n$

$30 = 30 + 0.45n$

Collect like terms

$0.45n = 30 - 30$

$0.45n =0$

$n = 0$

6 0

3 years ago

I need to divide this equation:

Luba_88 [7]

1+7/11 = 11/11+7/11 = 18/11 2+1/2 = 4/2+1/2 = 5/2 (18/11)/(5/2) = (18/11)*(2/5) = 36/55

5 0

3 years ago

Given that curl F = 2yi – 2zj + 3k, find the surface integral of the normal component of curl F (not F) over (a) the open hemisp

Dimas [21]

Use Stokes' theorem for both parts, which equates the surface integral of the curl to the line integral along the surface's boundary.

a. The boundary of the hemisphere is the circle $x^2+y^2=9$ in the plane $z=0$ , where the curl is $\mathrm{curl}\vec F=2y\,\vec\imath+3\,\vec k$ . Green's theorem applies here, so that

$\displaystyle\iint_S\mathrm{curl}\vec F\cdot\mathrm d\vec S=\int_{\partial S}\vec F\cdot\mathrm d\vec r=3\int_{x^2+y^2=9}\mathrm d\vec r$

which means the value of the line integral is 3 times the area of the circle, or $27\pi$ .

b. The closed sphere has no boundary, so by Stokes' theorem the integral is 0.

7 0

3 years ago