Nothing else is given, so for the two triangles to be congruent, the only possible proof is the ASA theorem.
first pairs of angles: 2x+7=x+21 => x=14
second pairs of angles: 8y-4=4y+28 =>y=8
The two triangles share the same side PR
Based on the Angle-Side-Angle Triangle Congruence theorem, these two triangles are congruent with x=14, y=8
(2x+7) +(8y-4) +Q=180 =>85
Answer:
G. 226 mm
Step-by-step explanation:
C=2(3.14)(36)
Step-by-step explanation:
Different Types of Indexes in SQL Server
The end behavior of the function y = x² is given as follows:
f(x) -> ∞ as x -> - ∞; f(x) -> ∞ as x -> - ∞.
<h3>How to identify the end behavior of a function?</h3>
The end behavior of a function is given by the limit of f(x) when x goes to both negative and positive infinity.
In this problem, the function is:
y = x².
When x goes to negative infinity, the limit is:
lim x -> - ∞ f(x) = (-∞)² = ∞.
Meaning that the function is increasing at the left corner of it's graph.
When x goes to positive infinity, the limit is:
lim x -> ∞ f(x) = (∞)² = ∞.
Meaning that the function is also increasing at the right corner of it's graph.
Thus the last option is the correct option regarding the end behavior of the function.
<h3>Missing information</h3>
We suppose that the function is y = x².
More can be learned about the end behavior of a function at brainly.com/question/24248193
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Answer:
7miles
equations shown in work image below
work shown on the paper with more explanations because text is hard to write equations (sorry I used km but it is miles for your problem.)
:) please give a heart for thanks
and brainliest crown :)
Step-by-step explanation:
For both d=r*t
Each bikes to others house and leave at the same time so for Tony,
11 = 30*t
t= 11/30 hours
for Gerry,
11 = 25*t
t= 11/25 hours
Comparing these, with LCD,
Tony's time is 55/150
Gerry's time is 66/150
So Tony got to Gerry's house 11/150 hours quicker than Gerry got to Tony's house.
Now they turn around and head back toward each other. If they leave at the same exact time, the elapsed time for each until they met would be the same so t (for tony) = t (for gerry), but Tony got a head start.
We start the stopwatch when Gerry turns around 11/150 hours after Tony has turned around. If Gerry's time to where they meet from Tony's house t(gerry), then Tony's time from Gerry's house is t(gerry) + 11/150