Answer:
To find the volume of a square-based pyramid, use the formula V = A(h/3), where V is the volume and A is the area of the base.
Step-by-step explanation:
a. The events are mutually exclusive, so

b. For the same reason,

Another way to see this is to use the result from part (a), and the inclusion/exclusion principle:

and the right side reduces to 0.
c. Same as (b),

d. Same as (b),

We can also use the distributivity rule for unions and intersections to write

e. If the
is the complement of
, then by DeMorgan's law,

<h3>500 PENCILS ARE GOT TO 1 SCHOOL. because 10 is divided by 5000 </h3>
The correct answer is: [A]: " <span>x(y – 5) = 2 " .
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Consider:
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Choice: [A]: " x(y–5) = 2 " ;
Divide each side by "x" ;
" [x(y – 5)] / x = 2/x " ;
→ y – 5 = 2/x ;
Add "5" to each side of the equation:
y – 5 + 5 = 2/x + 5 ;
→ y = 2/x + 5 ; not a line; since one cannot divide by "zero" ; there would be no "point" on the graph at "x = 0". So, this answer choice: [A] is correct.
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Choice [B]:
y -2x -18 = 0
y - 2x = 18
y = 18 + 2x ; y = 2x + 18 ; is a line.
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Choice C) 3y + 12 - 6x = 5 ;
3y = 5 - 12 + 6x ;
3y = -7 + 6x ; 3y = 6x - 7 ; y = 6x/3 - 7/3 ; y = 2x - 7/3 ; is a line.
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Choice: [D]:
2(y+x) = 0 ;
[2*(y+x)] / 2 = 0/2 ; y + x = 0 ; y = -x ; is a line.
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Count by 6 so 6×4 is 24 so 1/4