Answer:
![y=\frac{1}{2}x-7](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B2%7Dx-7)
Step-by-step explanation:
So we need to find an equation of a line that crosses the point (6,-4) and is perpendicular to y = -2x -3.
First, let's find the slope of the line we want to write. The line we want is perpendicular to y = -2x -3. Recall that if two lines are perpendicular to each other, their slopes are negative reciprocals of each other. What this means is that:
![m_1\cdot m_2=-1](https://tex.z-dn.net/?f=m_1%5Ccdot%20m_2%3D-1)
Plug -2 for one of the slopes.
![-2\cdot m_2=-1](https://tex.z-dn.net/?f=-2%5Ccdot%20m_2%3D-1)
Divide by -2 to find the slope of our line.
![m_2=1/2](https://tex.z-dn.net/?f=m_2%3D1%2F2)
Thus, our line needs to have a slope of 1/2.
Now, let's use the point-slope form. The point-slope form is given by:
![y-y_1=m(x-x_1)\\](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29%5C%5C)
Plug in 1/2 for the slope m and let's let our point (6,-4) be x₁ and y₁. Thus:
![y-(-4)=\frac{1}{2}(x-6)\\](https://tex.z-dn.net/?f=y-%28-4%29%3D%5Cfrac%7B1%7D%7B2%7D%28x-6%29%5C%5C)
Simplify and distribute:
![y+4=\frac{1}{2} x-3](https://tex.z-dn.net/?f=y%2B4%3D%5Cfrac%7B1%7D%7B2%7D%20x-3)
Subtract 4 from both sides:
![y=\frac{1}{2}x-7](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B2%7Dx-7)
The above is the equation that passes the point (6,-4) and is perpendicular to y = -2x -3.
Answer:
p =
and q = ![\frac{6}{13}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B13%7D)
Step-by-step explanation:
Given equations:
2p - 3q = 4 -----------(i)
3p + 2q = 9 ------------(ii)
Let's solve this equation simultaneously using the <em>elimination method</em>
(a) Multiply equation (i) by 3 and equation (ii) by 2 as follows;
[2p - 3q = 4] x 3
[3p + 2q = 9] x 2
6p - 9q = 12 -------------(iii)
6p + 4q = 18 -------------(iv)
(b) Next, subtract equation (iv) from equation (iii) as follows;
[6p - 9q = 12]
<u> - [6p + 4q = 18] </u>
<u> -13q = -6 </u> -----------------(v)
<u />
<u>(c)</u> Next, make q subject of the formula in equation (v)
q = ![\frac{6}{13}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B13%7D)
(d) Now substitute the value of q =
into equation (i) as follows;
2p - 3(
) = 4
(e) Now, solve for p in d above
<em>Multiply through by 13;</em>
26p - 18 = 52
<em>Collect like terms</em>
26p = 52 + 18
26p = 70
<em>Divide both sides by 2</em>
13p = 35
p = ![\frac{35}{13}](https://tex.z-dn.net/?f=%5Cfrac%7B35%7D%7B13%7D)
Therefore, p =
and q = ![\frac{6}{13}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B13%7D)
A circle would be the answer
Answer:
Oh wow
Step-by-step explanation:
Nice opinion xD
Well Jay has 20 phone numbers.
20j=13r-3x2 im not sure but i hope that helped a little.