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Tresset [83]
3 years ago
14

An airplane flies to San Francisco from Los Angeles in 4 hours. It flies back in 3 hours. If the wind is blowing from the north

at a velocity of 20 mph during both flights, what was the airspeed of the plane (its speed in still air)?
Mathematics
1 answer:
Sedaia [141]3 years ago
4 0

Answer:

Airspeed in still air:  140 mph

Step-by-step explanation:

Let s represent the speed in still air.  Recognize that the distance traveled is the same in either direction.

Also note that SF is north of LA.

Distance to SF from LA     =      Distance to LA from SF

(s-20)(mph)(4 hr)                 =    (s+20)(mph)(3 hr)

Then:

4s - 80 = 3s + 60 => s = 60 + 80 + 140 (mph)

The airspeed of the plane was 140 mph in still air.  With a tail wind, the plane  is faster; with a headwind, slower.

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sineoko [7]

Answer:

Volume of the tank = 636 ft³

Step-by-step explanation:

Formula for the volume of a cylinder is,

V = πr²h

Where r = radius of the cylinder

h = height of the cylinder

By substituting the values of radius and height of the water tank given in the question,

V = \pi (4.5)^{2}(10)

   = 202.5π

   = 202.5 × (3.14)

   = 635.85 ft³

   ≈ 636 ft³

Therefore, volume of the cylindrical water tank is 636 ft³.

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natali 33 [55]
What's the question?
7 0
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