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Tresset [83]
2 years ago
14

An airplane flies to San Francisco from Los Angeles in 4 hours. It flies back in 3 hours. If the wind is blowing from the north

at a velocity of 20 mph during both flights, what was the airspeed of the plane (its speed in still air)?
Mathematics
1 answer:
Sedaia [141]2 years ago
4 0

Answer:

Airspeed in still air:  140 mph

Step-by-step explanation:

Let s represent the speed in still air.  Recognize that the distance traveled is the same in either direction.

Also note that SF is north of LA.

Distance to SF from LA     =      Distance to LA from SF

(s-20)(mph)(4 hr)                 =    (s+20)(mph)(3 hr)

Then:

4s - 80 = 3s + 60 => s = 60 + 80 + 140 (mph)

The airspeed of the plane was 140 mph in still air.  With a tail wind, the plane  is faster; with a headwind, slower.

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What os the value of x in the equation 3x- 1/9y=18, when y =27
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6 0
3 years ago
Help! Algebra! please answer if you only know! and make it undertanding!
snow_lady [41]
1. a. Pretty much, you just have to rearrange it so that the highest power is in the front. So, here's your answer:
-6x^4+4x^2+2
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2. a. Since it's an odd power and a negative coefficient, it will be:
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3. a. This basically means that if you solve for x, you should get -2, 1, and 2. So, to do this, you can just write it in factored form and multiply inwards using any method of your choice (remember that in the parentheses, you should get the above value if you solve for x):
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Hope this helps!
6 0
3 years ago
Read 2 more answers
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