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solong [7]
3 years ago
8

To multiply 4 x 5 3/8, the mixed number can be broken down into a whole number and a fraction. In this case, that whole number w

ould be ____ and the fraction would be ___ eighths. Each of these parts are then ___ ___. Pls tell me the answer pls!
Mathematics
1 answer:
s2008m [1.1K]3 years ago
5 0

Answer:

Step-by-step explanation:

To multiply 4×5⅜, the mixed number can be broken down into a whole number and a fraction. In this case, that whole number would be 5 and the fraction would be three-eighths. Each of these parts are then multiplied by 4 and the products are added together.

4×5⅜ = 4×(5+⅜)

= 4×5 + 4×⅜

= 20 + 3/2

= 20 + 1½

= 21½

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Which of the following sets contains only rational numbers?
ICE Princess25 [194]

Answer: rational numbers

D. {3.2, 81, 45.41, √81}


3.2 = 32/10

45.41 = 4541/100

√81 = 9 = 9/1

3 0
3 years ago
I don't know how to do this. Can someone help me please?
Svetach [21]
1. y =220- x
150=220-70
5 0
3 years ago
Please help ASAP. PRE ALGEBRA
telo118 [61]

Answer:

x=35

Angle measurements of the triangle from least to greatest:

35,40,105

Step-by-step explanation:

The sum of the angles of a triangle is 180 degrees.

So we know that 40+3x+x=180.

First step is to combine the like  terms on the left hand side:

40+4x=180

Second step is to subtract 40 on both sides.

4x=140

Third step is to divide both sides by 4:

x=35

The angle that is given is the one that is 40 degrees.

So the angle whose measurement is x is really 35 degrees.

The angle whose measurement is 3x is real 3(35)=105 degrees.

In order from least to greatest we have:

35,40,105

6 0
3 years ago
Find+the+positive+value+for+α+if+the+radius+of+the+circle+3x^2+3y-6αx+12y-3α=0+is+4
Alik [6]

Answer:

\alpha=3

Step-by-step explanation:

<u>Equation of a Circle</u>

A circle of radius r and centered on the point (h,k) can be expressed by the equation

(x-h)^2+(y-k)^2=r^2

We are given the equation of a circle as

3x^2+3y^2-6\alpha x+12y-3\alpha=0

Note we have corrected it by adding the square to the y. Simplify by 3

x^2+y^2-2\alpha x+4y-\alpha=0

Complete squares and rearrange:

x^2-2\alpha x+y^2+4y=\alpha

x^2-2\alpha x+\alpha^2+y^2+4y+4=\alpha+\alpha^2+4

(x-\alpha)^2+(y+2)^2=r^2

We can see that, if r=4, then

\alpha+\alpha^2+4=16

Or, equivalently

\alpha^2+\alpha-12=0

There are two solutions for \alpha:

\alpha=-4,\ \alpha=3

Keeping the positive solution, as required:

\boxed{\alpha=3}

8 0
3 years ago
1. Rational or irrational?<br> 11/5
nignag [31]
The answer is irrational
4 0
3 years ago
Read 2 more answers
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