Answer:
The zeros of f(x) are -3, 2 , 6
Step-by-step explanation:
f(x) is a polynomial of degree 3.
If the polynomial is not factorized we will either factorize to find the zero or use trial and error method.
Since the f(x) in the question is in the factorized form. we will have to equate each factor to zero.
f(x) = (x+3)(x-2)(x-6)
x + 3 = 0 => x = -3
x - 2 = 0 => x = 2
x - 6 = 0 => x = 6
The expression that would be added to both sides is (b/2a)^2
<h3>How to determine the expression?</h3>
The equation is given as:
x^2 + b/ax + __ = c/a + __
Take the coefficient of x
b/a
Divide by 2
b/2a
Square the expression
(b/2a)^2
Hence, the expression that would be added to both sides is (b/2a)^2
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The improper fraction to that is 167/3