So,
The ratio of dogs to cats:
The other proportion:
5 times 28 is 140.
Multiply the fraction by the appropriate form of 1
There are 56 dogs when the number of cats is 140.
Answer: 35
the age of Roberto is x (x > 3)(x ∈ N)
because Roberto is 3 years older than Carolyn => the age of Carolyn is x - 3
in 7 years, the age of Roberto is x + 7; the age of Carolyn is x - 3 + 7 = x + 4
because In 7 years the sum of their ages will be 81 =>
x + 7 + x + 4 = 81
⇔ 2x + 11 = 81
⇔ 2x = 70
⇔ x = 70/2 = 35
=> the age of Roberto is 35
Step-by-step explanation:
H = 2f / (m+1)
[multiply by (m+1)]
h(m+1) = 2f
[divide by 2]
f = (h (m + 1)) / 2
3b / (b+2) = 12 / (b+2)
[multiply by (b+2)]
3b = 12
[divide by 3]
b = 4
3 / (6x + 1) / 2 = 8 / (x + 4) / 3
[multiply both denominators to mike one denominator]
3 / 8(6x+1) = 8 / 3(x+4)
[expand brackets]
3 / (48x + 8) = 8 / (3x + 12)
[multiply by (48x + 8)]
3 = 8(48x + 8) / (3x+12)
[multiply by (3x+12)]
3(3x +12) = 4(48x + 8)
[simplify]
9x + 36 = 192x + 32
173x = 4
x = 4 / 173
Answer:
m=3/4
Step-by-step explanation:
Step 1
Let n represent car and m represent motorcycles.
n + m = 50 ...................1
car has four wheels and motorcycle has two wheels
4n + 2m = 164 .............................. 2
Step 2
Solve equation 1 and 2 simultaneously.
from (1), make n subject of relation and substitute in equation 2.
n = 50 - m
Step 3
Substitute n in equation 2
4(50 - m) + 2m = 164
200 - 4m + 2m = 164
collect like terms
200 - 164 = 4m - 2m
36 = 2m
m = 36/2
m = 18
next find n
n = 50 - m
n = 50 - 18
n = 32
There are 32 cars and 18 motorcycles.
