Graph the following equation.<br> y + 2 = -2/3(x-4)

2 (-4) (-5) =<br> Whats the awnser cause my brain cant HANNDLE THIS

Ganezh [65]

Answer:

40

Step-by-step explanation:

2 x -4 x -5 = 2 x 20 = <u>40</u>

5 0

3 years ago

1. A quadratic equation can have all of the following number of solutions except

mina [271]

You cannot have infinite solutions.

7 0

3 years ago

A random sample of of 100 voters in a town is selected, and 24 are found to support an annexation suit. Find the 96% confidence

lbvjy [14]

Answer: 0.24 +/- 0.088 = (0.152, 0.328)

Step-by-step explanation:

The point estimate p is given by;

p= 24/ 100 = 0.24

Z value for 96% confidence interval is 2.05

The solution for the given confidence interval is derived using the equation

p +/- z√(pq/n)

Where p = 0.24 q= 1-p = 0.76, n=100 z= 2.05

= 0.24 +/- 2.05√(0.24×0.76/100)

= 0.24 +/- 2.05(0.0427)

=0.24 +/- 0.088

= ( 0.152, 0.328)

6 0

3 years ago

Convert the following to scientific notation: 0.000665.

BaLLatris [955]

- - Step 1: Move the decimal point to the right, until you get greater then 1 and less than 10. In this case we moved it till we got 6.65.
- - Step 2: Count how many times you moved the decimal over: In this case, we moved it 4 times.
- - Step 3: All you have to do now is chose which one has 6.65 over -4.
(We are saying negative because when you move it to the right, it becomes negative.)
Final answer: A

8 0

3 years ago

Read 2 more answers

Indicate the equation of the given line in standard form. Show all your work for full credit. the line containing the median of

alukav5142 [94]

Answer:

* The equation of the median of the trapezoid is 10x + 6y = 39

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line whose end points are (x1 , y1) , (x2 , y2) is

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

- The mid point of the line whose end point are (x1 , y1) , (x2 , y2) is

$(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

- The standard form of the linear equation is Ax + BC = C, where

A , B , C are integers and A , B ≠ 0

- The median of a trapezoid is a segment that joins the midpoints of

the nonparallel sides

- It has two properties:

# It is parallel to both bases

# Its length equals half the sum of the base lengths

* Lets solve the problem

- The trapezoid has vertices R (-1 , 5) , S (! , 8) , T (7 , -2) , U (2 , 0)

- Lets find the slope of the 4 sides two find which of them are the

parallel bases and which of them are the non-parallel bases

# The side RS

∵ $m_{RS}=\frac{8-5}{1 - (-1)}=\frac{3}{2}$

# The side ST

∵ $m_{ST}=\frac{-2-8}{7-1}=\frac{-10}{6}=\frac{-5}{3}$

# The side TU

∵ $m_{TU}=\frac{0-(-2)}{2-7}=\frac{2}{-5}=\frac{-2}{5}$

# The side UR

∵ $m_{UR}=\frac{5-0}{-1-2}=\frac{5}{-3}=\frac{-5}{3}$

∵ The slope of ST = the slop UR

∴ ST// UR

∴ The parallel bases are ST and UR

∴ The nonparallel sides are RS and TU

- Lets find the midpoint of RS and TU to find the equation of the

median of the trapezoid

∵ The median of a trapezoid is a segment that joins the midpoints of

the nonparallel sides

∵ The midpoint of RS = $(\frac{-1+1}{2},\frac{5+8}{2})=(0,\frac{13}{2})$

∵ The median is parallel to both bases

∴ The slope of the median equal the slopes of the parallel bases = -5/3

∵ The form of the equation of a line is y = mx + c

∴ The equation of the median is y = -5/3 x + c

- To find c substitute x , y in the equation by the coordinates of the

midpoint of RS

∵ The mid point of Rs is (0 , 13/2)

∴ 13/2 = -5/3 (0) + c

∴ 13/2 = c

∴ The equation of the median is y = -5/3 x + 13/2

- Multiply the two sides by 6 to cancel the denominator

∴ The equation of the median is 6y = -10x + 39

- Add 10x to both sides

∴ The equation of the median is 10x + 6y = 39

* The equation of the median of the trapezoid is 10x + 6y = 39

7 0

3 years ago

Graph the following equation. y + 2 = -2/3(x-4)