Determine whether the point 1,5 is a solution to the system of inequalities below y>3x , y>/2x+1
Answer:
![\sqrt[5]{25x^{2}y^{4}z^{6} }](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B25x%5E%7B2%7Dy%5E%7B4%7Dz%5E%7B6%7D%20%7D)
Step-by-step explanation:
going to the 2/5 power is the the fifth root of a square. For fraction exponents going into radical form use the denominator as you root of and use the numerator as the exponent of the rest making sure to multiply any other exponents by that number and when there is no exponent treat it as having an exponent of one for the multiplying.
For a 7 sides polygon which is called heptagon or septagon
Interior angles = (7-2)*180/7 = 128.57°
Exterior angle = 180 - 128.57 = 51.43°
Central angle = 360/7 = 51.43°
The statements which are correct:
<span>3. The regular polygon ABCDEFG can be broken down into 2 isosceles trapezoids and 1 isosceles triangle
</span>
<span>5. The central angle of the polygon ABCDEFG is about 51.43° and each interior angle is about 128.57°
</span>
<span>7. The central angle ABCDEFG is the same measure of the exterior angle
</span>
Answer:
If the line RS has been rotated 90 degrees, then VU will be perpendicular to RS and the two slopes must be opposite and reciprocal, i.e. product of the two slopes will equal -1.
As a verification, we find the locations of V and U from rotations of R & S.
(actually, the triangle had been rotated -90°, 90 ° clockwise)
Step-by-step explanation:
Slope RS, m1:
Slope VU, m2
Hence m1*m2=1*-1=-1, meaning that m1 and m2 are opposite (in sign) and are reciprocal to each other, as expected
