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Olenka [21]
4 years ago
15

What is a whole number greater than 4.5

Mathematics
2 answers:
Anna71 [15]4 years ago
7 0
The answer is 5. Cause 5 is one point greater than 4.5







dezoksy [38]4 years ago
5 0

Answer:

5

Step-by-step explanation:

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Find g(x)-f(x). g(x)=x^2+1 and f(x)=2x+5
UkoKoshka [18]

Answer:

g(x) - f(x) = x^{2} - 2x - 4

Step-by-step explanation:

g(x) - f(x) = (x^{2} + 1) - (2x + 5)

<em><u>Multiply the -1 in then add the two expressions together.</u></em>

(x^{2} + 1) + (-2x - 5) = x^{2} - 2x - 4

8 0
4 years ago
A circular pool with a 10 foot diameter is surrounded by a deck. What is the area of the deck which surrounds the pool? use 3.14
zavuch27 [327]

Answer:

146.5 sq. feet.

Step-by-step explanation:

Area of the deck = Large Square (with 15 ft side) - Circular Pool (with radius 10/2=5)

Large Square area = s^2=(15)^2=225

Circular Pool area = \pi r^2=\pi (5)^2=\pi (25)\\=25(3.14)\\=78.5

Thus, area of deck surrounding pool = 225-78.5=146.5 sq. feet

7 0
4 years ago
Read 2 more answers
Determine whether each figure creates the conditions to form a unique triangle, more than one triangle, or no triangle.
frutty [35]

Answer:

im like 95% sure its a unique triangle

Step-by-step explanation:

8 0
3 years ago
Find the distance between each pair if points
sukhopar [10]

Answer:

point a is positive but point b is negative

6 0
3 years ago
You are trying to heat up a cup of water with a butane lighter.
algol13

Answer:

Step-by-step explanation:

Remark

The formula for this is

Heat = m * c * Δt

Givens

Heat = unknown

m = 200 grams

c = 4.184 Joules / grams oC

Δt = the change in temperature = 35.7 - 22.3 = 13.4

Solution

Heat = 200 * 4.184 * 13.4

Heat = 11213 Joules

Heat = 11.2 Kj

It's hard to get the correct number of sig digs because the 200 is not qualified in any way.

Part 2.

This can really puzzle you until you know that heat given up = the heat taken on. The heat taken on was 11.2 Kj. The Butane lighter must have given that heat on.

Heat of Combustion = Heat Given Up / Number grams burned.

Heat of Combustion = 11.2 Kj / 0.23 grams

Heat of Combustion = 48.8 Kj / gram

8 0
3 years ago
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