Question

13. (4r⁰)⁴ 14. (4a³)² 15. (3k⁴)⁴ 16. (4xy)⁻¹ 17. (2b⁴)⁻¹ 18. (x²y⁻¹)₂

Answer 1

Answer:

Step-by-step explanation:

13.

(4r⁰)⁴

= (4×1)⁴

= (4)⁴

= 256

14.

(4a³)²

$= 4^2a^{(3\times 2)}$

= 16 a⁶

15.

(3k⁴)⁴

$= 3^4 k^{4*4}$

$= 81 \ k^{16}$

16.

(4xy)⁻¹

$= \dfrac{1}{4 xy}$

17.

(2b⁴)⁻¹

$= \dfrac{1}{2 \ b^4}$

18.

(x²y⁻¹)²

$=\Big ( \dfrac{x^2}{y} \Big) ^ 2$

$=\Big ( \dfrac{x^4}{y^2} \Big)$