The equation of the circle that passes through the point (0 , 4) and has a center at the origin is x^2 + y^2 = 16.
Using the distance formula, get the radius of the circle by solving for the distance between the center and the point (0 , 4).
radius = distance = √(x2 - x1)^2 + (y2 - y1)^2
radius = √(0 - 0)^2 + (4 - 0)^2
radius= √0 + 16
radius = 4
The standard form of the equation of the circle is given by (x - h)^2 + (y - k)^2 = r^2, where (h , k) is the location of the center and r is the radius of the circle.
Given the radius and center of the circle, substitute these values to the standard form of the equation of the circle.
(x - h)^2 + (y - k)^2 = r^2
where (h , k) = (0 , 0)
r = 4
(x - 0)^2 + (y - 0)^2 = 4^2
x^2 + y^2 = 16
Learn more about equation of a circle here: brainly.com/question/14150470
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Answer:
Function 1 is linear
Step-by-step explanation:
A linear is a straight line on the graph.
Yes it is true that point , line and pair of intersecting lines are special cases of conic sections
They are actually degenerate cases of intersection that occurs in special conditions.
Lets get into a bit detail one by one
A single point - when the plane which cuts the surface of cone only passes through apex
Again when the plane passes through apex and another point on the cone
it produces one straight line or two intersecting straight lines.
7 x 11 + 6 x (11 - 5)
= 77 + 6 x 6
= 77 + 36
= 113 ft^2