Problem 3: Let x = price of bag of pretzels Let y = price of box of granola bars
We have Lesley's purchase: 4x+2y=13.50
And Landon's: 1x+5y=17.55
We can use the elimination method. Let's negate Landon's purchase by multiplying by -1. -1x-5y=-17.55
We add this four times to Lesley's purchase to eliminate the x variable.
2y-20y=13.50-70.2
-18y=-56.7
y = $3.15 = Price of box of granola bars
Plug back into Landon's purchase to solve for pretzels.
x+5*3.15=17.55
x+15.75=17.55
x = $1.80 = price of bag of pretzels
Problem 4.
Let w = number of wood bats sold
Let m = number of metal bats sold
From sales information we have: w + m = 23
24w+30m=606
Substitution works well here. Solve for w in the first equation, w = 23 - m, and plug this into the second.
24*(23-m)+30m=606
552-24m+30m=606
6m=54
m=9 = number of metal bats sold
Therefore since w = 23-m, w = 23-9 = 14. 14 wooden bats were sold.
Answer:
Step-by-step explanation:
x+165 = 180
x = 180 - 165
x = 15
The formula is
I=prt
I interest earned 2800
P amount deposited. ?
R interest rate 0.045
T time 4.5 years
Solve the formula for p by dividing both sides by rt to get
P=I/rt
P=2,800÷(0.045×4.5)
P=13,827.16 round your answer to get 13827
Hope it helps!
Answer:
y=9x+2
Step-by-step explanation:
The standard form for a linear equation is y=mx+b. m=9 since it is slope and b=2 which is the y intercept. So the equation would be y=9x+2.
The answer is A = P²/16
The perimeter P of a square is sum of its sides s: P = s + s + s + s = 4s
The area A of a square with side s is: A = s * s = s²
Step 1: Solve s from the formula for the perimeter.
Step 2: substitute s from the formula for the perimeter into the formula for the area.
Step 1:
P = 4s
s = P/4
Step 2:
A = s²
s = P/4
A = (P/4)²
A = P²/4²
A = P²/16
