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Triss [41]
3 years ago
15

I Need help please I only have a little bit of time

Mathematics
2 answers:
kvasek [131]3 years ago
6 0

Answer:

30

Step-by-step explanation:

if its asking for inches

Ratling [72]3 years ago
4 0
30 it asks for inches♥️
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26. The cost of a television set has increased continuously by 2%. In 1999, the average
RUDIKE [14]

Answer:

<u>The exponential model is: Cost after n years = 400 * (1 + 0.02)ⁿ</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Cost of the TV set in 1999 = US$ 400

Annual increase rate = 2% = 0.02

2. Write an exponential model to represent this data.

Cost after n years = Cost in 1999 * (1 + r)ⁿ

where r = 0.02 and n = the number of years since 1999

Replacing with the real values for 2020, we have:

Cost after 21 years = 400 * (1 + 0.02)²¹

Cost after 21 years = 400 * 1.5157

Cost after 21 years = $ 606.28

The TV set costs $ 606.28 in 2020.

<u>The exponential model is: Cost after n years = 400 * (1 + 0.02)ⁿ</u>

8 0
3 years ago
The Bobcat baseball team has a total of 53 games this season. There are 9 games in the first month. After the first month, the t
lisabon 2012 [21]

Answer:

The season will last 4 months after the first month (5 months in total)

Step-by-step explanation:

53 games

9 games first month

11 games per month (since the second one)

x - number of months

9 + 11x = 53

11x = 53-9

11x = 44

x = 4

5 0
3 years ago
EXPERTS/ACE/GENIUSES PLZ HELP
Llana [10]
Sqrt(2)  = 1.41
 so it would be between 1 and 2

Answer is A
7 0
3 years ago
Use the arc length formula to find the length of the curve y = 4x − 5, −1 ≤ x ≤ 2. check your answer by noting that the curve is
professor190 [17]
Ok, here we go.  Pay attention.  The formula for the arc length is AL= \int\limits^b_a { \sqrt{1+( \frac{dy}{dx})^2 } } \, dx.  That means that to use that formula we have to find the derivative of the function and square it.  Our function is y = 4x-5, so y'=4.  Our formula now, filled in accordingly, is AL= \int\limits^2_1 { \sqrt{1+4^2} } \, dx (that 1 is supposed to be negative; not sure if it is til I post the final answer).  After the simplification we have the integral from -1 to 2 of \sqrt{17}.  Integrating that we have AL= \sqrt{17}x from -1 to 2.  2 \sqrt{17}-(-1 \sqrt{17} ) gives us 3 \sqrt{17}.  Now we need to do the distance formula with this.  But we need 2 coordinates for that.  Our bounds are x=-1 and x=2.  We will fill those x values in to the function and solve for y.  When x = -1, y=4(-1)-5 and y = -9.  So the point is (-1, -9).  Doing the same with x = 2, y=4(2)-5 and y = 3.  So the point is (2, 3).  Use those in the distance formula accordingly: d= \sqrt{(2-(-1))^2+(3-(-9))^2} which simplifies to d= \sqrt{9+144}= \sqrt{153}.  The square root of 153 can be simplified into the square root of 9*17.  Pulling out the perfect square of 9 as a 3 leaves us with 3 \sqrt{17}.  And there you go!
5 0
3 years ago
(4,-5) (3,5)<br> slope =<br> What is the slope of this equation?
galben [10]
The slope is -10, I used a graph for this.
4 0
3 years ago
Read 2 more answers
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