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2 years ago

Evaluate the expression 6 + 4x {3+ 7).

Mathematics

2 answers:

myrzilka [38]2 years ago

8 0

I think it’s 2(3+20x)

Mama L [17]2 years ago

6 0

Answer:

40x + 6

Step-by-step explanation:

6 + 4x (3 + 7)

6 + 12x + 28x

40x + 6

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Which strategy would you use to find 2plus8?explain

nika2105 [10]

it is 10...,,,,....,,,,,,,,,,?,,?????

8 0

3 years ago

A point $(x, y)$ with integer coordinates is randomly selected such that $0 \le x \le 8$ and $0 \le y \le 4$. what is the probab

ahrayia [7]

Answer:

$\frac{1}{3}$

Step-by-step explanation:

A point (x, y) with integer coordinates is randomly selected such that $0 \le x \le 8 \:and\: $0 \le y \le 4$.$

The possible pairs of (x,y) are:

(0,0),(0,1),(0,2),(0,3),(0,4)

(1,0),(1,1),(1,2),(1,3),(1,4)

(2,0),(2,1),(2,2),(2,3),(2,4)

(3,0),(3,1),(3,2),(3,3),(3,4)

(4,0),(4,1),(4,2),(4,3),(4,4)

(5,0),(5,1),(5,2),(5,3),(5,4)

(6,0),(6,1),(6,2),(6,3),(6,4)

(7,0),(7,1),(7,2),(7,3),(7,4)

(8,0),(8,1),(8,2),(8,3),(8,4)

The Total Possible Outcomes n(S)= 45

The pair (x, y) that satisfies the given condition (say event A: $x + y \le 4$ ) are:

$(0,0),(0,1),(0,2),(0,3),(0,4)\\(1,0),(1,1),(1,2),(1,3)\\(2,0),(2,1),(2,2)\\(3,0),(3,1)\\(4,0)$

n(A)=15

Therefore:

$P(A)=\frac{n(A)}{n(S)} =\frac{15}{45} =\frac{1}{3}$

5 0

3 years ago

What is the length of the line segment between A(–5, 8) and B(7, 8)? (1 point) • 2 units • 3 units • 12 units • 13 units

salantis [7]

The y-coordinates are the same, so the length of this horizontal line segment is the difference between the x-coordinates.

Length = 7 - (-5) = 12 units

6 0

3 years ago

An arched drainage culvert can be modelled by the function:

Zanzabum

Substitute 136.5 for y.

$136.5=\frac{x(191-x)}{60}$

$8190=x(191-x)$

$8190=191x-x^{2}$

$x^{2} -191x+8190=0$

Compare this equation with $ax^{2} +bx+c=0$

a = 1, b = - 191, c = 8190

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2}$ or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2}$

$x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2}$ or

$x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}$

$x=\frac{191+\sqrt{36481-32760 } }{2}$ or

$x=\frac{191-\sqrt{36481-32760 } }{2}$

$x=\frac{191+\sqrt{3721 } }{2}$ or

$x=\frac{191-\sqrt{3721 } }{2}$

$x=\frac{191+61}{2}$ or

$x=\frac{191-61}{2}$

$x=\frac{252}{2}$ or

$x=\frac{130}{2}$

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = $\sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}$

= $\sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}$

= 126 - 65

= 61

Hence, width of the air space is 61m.

5 0

2 years ago

Given that AB parallels QR, AB bisects AE, QR bisects QT

enyata [817]

Answer:

1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'

2. Translate A' to Q

Step-by-step explanation:

We notice the triangles have the same orientation, so no reflection or rotation is involved. The desired mapping can be accomplished by dilation and translation:

1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'

2. Translate A' to Q

The result will be that ΔA"B"E" will lie on top of ΔQRT, as required.

5 0

2 years ago