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Kaylis [27]
2 years ago
7

I need help ASAP it’s due in 30 mins

Biology
1 answer:
finlep [7]2 years ago
6 0

Answer:

Explanation:

I wasn't sure what the letters the trait was supposed to be so I used S and s.

1.  male

2. has the trait

3.  recessive

4. Ss

5. ss

6. Ss

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Answer:

See the answer below

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Null hypothesis: The two genes are independently assorting and therefore, are not linked to each other.

Let A represents the allele for tail length and B for fur color. Long-tail A is dominant over short tail a while brown fur B is dominant over white fur b.

For the first cross involving true-breeding mice:

    AABB   x   aabb

F1         AaBb (long tails and brown fur)

For the second cross:

      AaBb   x   aabb

4 AaBb - Long-tail, brown fur

4 Aabb - Long tail, white fur

4 aaBb - short tail, brown fur

4 aabb - short tail, white fur

Since the phenotypic ratio from the cross is 1:1:1:1, if the null hypothesis was to be true, it means that the expected phenotype ratio should be 1:1:1:1.

In order to test this hypothesis, we use Chi-square:

phenotype                           O            E                 X^2  

Long-tail, brown fur           118          97.5        \frac{(118-97.5)^2}{97.5} = 4.31

Long tail, white fur              77           97.5             4.31

short tail, brown fur             81           97.5              2.79

short tail, white fur              114           97.5              2.79

Total                                                                          14.2

Degree of freedom = 4 - 1 = 3

Critical Chi-square value = 7.815

The calculated Chi-square value is more than the critical value, hence, the null hypothesis is rejected.

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