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3 years ago

State if the scenario involves a permutation or a combination. Then find the number of possibilities.

Mathematics

1 answer:

Blizzard [7]3 years ago

8 0

Answer:

Permutation. ; 83810 ways

Step-by-step explanation:

Permutation and combination methods refers to mathematical solution to finding the number of ways of making selection for a group of objects.

Usually, selection process whereby the order of selection does not matter are being treated using permutation, while those which takes the order of selection into cognizance are calculated using combination.

Here, selecting 2 members (president and vice president) from 290 ; since order of arrangement does not matter, we use permutation ;

Recall :

nPr = n! ÷ (n - r)!

Hence,

290P2 = 290! ÷ (290 - 2)!

290P2 = 290! ÷ 288!

290P2 = (290 * 289) = 83810 ways

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Read 2 more answers

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<h2>Explanation:</h2><h2></h2>

Hello! Remember you have to write complete questions in order to get good and exact answers. Here you forgot to write the relation so I could help you providing my own relation.

Remember that for any relation, we have a set $A$ that matches the the domain (also called the set of inputs) of the function and the set $B$ that contains the range (also called the set of outputs).

Suppose our relation is:

$y=-10+x \\ \\ For \ x=1,2,3,4,5$

So the x-values represents the set A and the y-values the set B. Therefore, by evaluating the x-values into our relation we get:

$\text{If x=1} \\ \\ y=-10+1=-9 \\ \\ \\ \text{If x=2} \\ \\ y=-10+2=-8 \\ \\ \\ \text{If x=3} \\ \\ y=-10+3=-7 \\ \\ \\ \text{If x=4} \\ \\ y=-10+4=-6 \\ \\ \\ \text{If x=5} \\ \\ y=-10+5=-5$

So in this context, the correct option is:

B) (-9,-8, -7, -6, -5}

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