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sleet_krkn [62]
3 years ago
5

What equation results from completing the square and then factoring? x2 + 6x = 13

Mathematics
2 answers:
larisa [96]3 years ago
7 0
Step 1: Subtract 13 from both sides.
<span><span><span><span>x^2</span>+<span>6x</span></span>−13</span>=<span>13−13</span></span><span><span><span><span>x^2</span>+<span>6x</span></span>−13</span>=0</span>
Step 2: Use quadratic formula with a=1, b=6, c=-13.
<span>x=<span><span><span>−b</span>±<span>√<span><span>b2</span>−<span><span>4a</span>c</span></span></span></span><span>2a</span></span></span><span>x=<span><span><span>−<span>(6)</span></span>±<span>√<span><span><span>(6)</span>2</span>−<span><span>4<span>(1)</span></span><span>(<span>−13</span>)</span></span></span></span></span><span>2<span>(1)
</span></span></span></span><span>x=<span><span><span>−6</span>±<span>√88</span></span>2
</span></span><span><span>x=<span><span>−3</span>+<span><span><span>√22</span><span> or </span></span>x</span></span></span>=<span><span>−3</span>−<span>√22
</span></span></span>Answer would be 
<span><span>x=<span><span>−3</span>+<span><span><span>√22</span><span> or </span></span>x</span></span></span>=<span><span>−3</span>−<span>√<span>22</span></span></span></span>
levacccp [35]3 years ago
7 0

Apex answer (x+3)^2=22

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Find a particular solution to the nonhomogeneous differential equation y'' + 4 y = cos(2x) + sin(2x).
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The characteristic solution follows from solving the characteristic equation,

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y_c=C_1\cos2x+C_2\sin2x

A guess for the particular solution may be a\cos2x+b\sin2x, but this is already contained within the characteristic solution. We require a set of linearly independent solutions, so we can look to

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Substituting into the ODE, you have

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Therefore the particular solution is

y_p=-\dfrac14x\cos2x+\dfrac14x\sin2x

Note that you could have made a more precise guess of

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6 0
3 years ago
Given that rectangle MNOP rectangle STUV what is the length of TU
Lerok [7]

Answer:

TU = 22.5 units

Step-by-step explanation:

Given that the rectangles are similar then the ratios of corresponding sides are equal, that is

\frac{UV}{OP} = \frac{TU}{NO}, substitute values, note NO = MP = 15

\frac{9}{6} = \frac{TU}{15} ( cross- multiply )

6TU = 135 ( divide both sides by 6 )

TU = 22.5 units

7 0
3 years ago
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