Step 1: Subtract 13 from both sides. <span><span><span><span>x^2</span>+<span>6x</span></span>−13</span>=<span>13−13</span></span><span><span><span><span>x^2</span>+<span>6x</span></span>−13</span>=0</span> Step 2: Use quadratic formula with a=1, b=6, c=-13. <span>x=<span><span><span>−b</span>±<span>√<span><span>b2</span>−<span><span>4a</span>c</span></span></span></span><span>2a</span></span></span><span>x=<span><span><span>−<span>(6)</span></span>±<span>√<span><span><span>(6)</span>2</span>−<span><span>4<span>(1)</span></span><span>(<span>−13</span>)</span></span></span></span></span><span>2<span>(1) </span></span></span></span><span>x=<span><span><span>−6</span>±<span>√88</span></span>2 </span></span><span><span>x=<span><span>−3</span>+<span><span><span>√22</span><span> or </span></span>x</span></span></span>=<span><span>−3</span>−<span>√22 </span></span></span>Answer would be <span><span>x=<span><span>−3</span>+<span><span><span>√22</span><span> or </span></span>x</span></span></span>=<span><span>−3</span>−<span>√<span>22</span></span></span></span>
The square root of 121 is 11. 11x11=121 which makes the square root of 121, 11. The cube root of 125 is 5. Cube roots are numbers that are multiplied by each other to make a number, 125 is 5x5x5 so the cube root is 5. 11 is a greater number than 5 which makes the square root of 121 greater.
