The original perimeter is 22 cm.
If both sides are doubled, the length would be 16 cm and the width would be 6 cm.
The perimeter would be 44 cm.
22/44 is 50%.
For the first question the answer is C(n)=0.75n-0.25
for the second question the answer is y=2x
Answer:
l = 16 cm
Step-by-step explanation:
Let's set the width of the rectangle as "w" and the length of the rectangle as "w/2 + 9".
The perimeter of a rectangle is calculated by adding up the value of all of its side lengths. Therefore, we can find the perimeter using 2l + 2w = P.
We can substitute 60 for P and w/2 + 9 for l.
- 2(w/2 + 9) + 2w = 60
- 2w/2 + 18 + 2w = 60
- w + 18 + 2w = 60
- 3w + 18 = 60
- 3w = 42
- w = 14
Substitute w = 14 into the equation for length l.
- l = w/2 + 9
- l = 14/2 + 9
- l = 16
The length of the rectangle is 16 cm.
Answer:
2/8(x) - 4 = 2
<em>Hope this helps! </em>
What are the numbers for the other ones?
