SOLVE BY ELIMINATION. x-2y=2 3x+y=6

1 answer:

7 0

$\left \{ {{x-2y=2} \atop {3x+y=6\ |\cdot2}} \right. \\\\ \left \{ {{x-2y=2} \atop {6x+2y=12}} \right. \\+-----\\\\7x=14\ \ \ \ |:7\\x=2\\\\2-2y=2\\-2y=2-2\\-2y=0\\y=0\\\\ \left \{ {{y=0} \atop {x=2}} \right.$

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