Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer
(x-1) (x-4)
Step-by-step explanation:
I did this not long ago in class so that's the answer
Answer:
Let's simplify step-by-step.
14xy+3xy+2x(y−17)
=19xy−34x
Answer:
10x
Step-by-step explanation:
Answer:
smallest number of chickens= 3
Step-by-step explanation:
In this question the given formation is:
two chickens in front of a chicken
the total number of chickens are 3
two chickens behind a chicken
the total number of chickens are 3
a chicken between two chickens
the total number of chickens are 3
So, the smallest number of chicken that can be required to make this formation will be 3.
So, if we consider that the chickens are walking in a straight line, two (2nd and 3rd) chickens will be behind the 1st chicken, two chickens( 1st and 2nd) will be in front of the last (3rd) chicken and one (2nd) chicken is in the middle of two (between 1st and 3rd) chicken.