<h2>>>> Answer <<<</h2>
Let's check which polynomial is divisible by ( x - 1 ) using hit , trial and error method .
A ( x ) = 3x³ + 2x² - x
The word " divisible " itself says that " it is a factor "
Using factor theorem ;
Let;
=> x - 1 = 0
=> x = 1
Substitute the value of x in p ( x )
p ( 1 ) =
3 ( 1 )³ + 2 ( 1 )² - 1
3 ( 1 ) + 2 ( 1 ) - 1
3 + 2 - 1
5 - 1
4
This implies ;
A ( x ) is not divisible by ( x - 1 )
Similarly,
B ( x ) = 5x³ - 4x² - x
B ( 1 ) =
5 ( 1 )³ - 4 ( 1 )² - 1
5 ( 1 ) - 4 ( 1 ) - 1
5 - 4 - 1
5 - 5
0
This implies ;
B ( x ) is divisible by ( x - 1 )
Similarly,
C ( x ) = 2x³ - 3x² + 2x - 1
C ( 1 ) =
2 ( 1 )³ - 3 ( 1 )² + 2 ( 1 ) - 1
2 ( 1 ) - 3 ( 1 ) + 2 - 1
2 - 3 + 2 - 1
4 - 4
0
This implies ;
C ( x ) is divisible by ( x - 1 )
Similarly,
D ( x ) = x³ + 2x² + 3x + 2
D ( 1 ) =
( 1 )³ + 2 ( 1 )² + 3 ( 1 ) + 2
1 + 2 + 3 + 2
8
This implies ;
D ( x ) is not divisible by ( x - 1 )
<h2>Therefore ; </h2>
<h3>B ( x ) & C ( x ) are divisible by ( x - 1 ) </h3>
Answer:
six raised to the one twelfth power
Step-by-step explanation:
The cubed root of 6/the fourth root of 6 equals (6^1/3)/(6^1/4)
6^((1/3)-(1/4))
6^((4-3)/12)
6^1/12
the answer to this is x= -1
Answer:
Step-by-step explanation:
Perimeter of Square = 40 cm
4*side = 40
side = 40/4
side = 10 cm
Area of shaded region= Area of square - [Area of triangle 1 + Area of triangle 2]
![=[side*side]-[\frac{1}{2}*b*h+\frac{1}{2}*b*h]\\\\=[10*10]-[\frac{1}2}*3*10+\frac{1}{2}*10*6]\\\\=100-[3*5+5*6]\\\\=100-[15+30]\\\\=100-45\\\\=55cm^{2}\\](https://tex.z-dn.net/?f=%3D%5Bside%2Aside%5D-%5B%5Cfrac%7B1%7D%7B2%7D%2Ab%2Ah%2B%5Cfrac%7B1%7D%7B2%7D%2Ab%2Ah%5D%5C%5C%5C%5C%3D%5B10%2A10%5D-%5B%5Cfrac%7B1%7D2%7D%2A3%2A10%2B%5Cfrac%7B1%7D%7B2%7D%2A10%2A6%5D%5C%5C%5C%5C%3D100-%5B3%2A5%2B5%2A6%5D%5C%5C%5C%5C%3D100-%5B15%2B30%5D%5C%5C%5C%5C%3D100-45%5C%5C%5C%5C%3D55cm%5E%7B2%7D%5C%5C)
Percentage = (55/100)*100=55%
