Answer:
25
Step-by-step explanation:
When we write expressions for the total cost of each field visit and set them equal, we find the solution to be the ratio of the difference in fixed cost to the difference in variable cost.
y = 75 +7x . . . . . cost for x students to visit the science center
y = 50 +8x . . . . cost for x students to visit the natural history museum
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Subtracting the first equation from the second, we get ...
0 = -25 +x
25 = x . . . . . add 25; the number of students such that costs are equal
The cost will be the same either place for 25 students.
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<em>Additional comment</em>
Here, the fixed cost difference is 75-50=25, and the variable cost difference is 8-7=1. The ratio of these costs is ...
$25/($1 /student) = 25 students.
This relationship only holds when the higher fixed cost is associated with the lower variable cost. Charges are such that one place caters to larger numbers of students (science center), and one prefers fewer students (natural history museum).
Answer:
0.1527
Step-by-step explanation:
Given that a researcher wishes to conduct a study of the color preferences of new car buyers.
Suppose that 50% of this population prefers the color red
15 buyers are randomly selected
Let X be the no of buyers who prefer red.
X has exactly two outcomes red or non red.
Also each buyer is independent of the other
Hence X is binomial with p = 0.5 and n = 15
Required prob =The probability that exactly three-fifths of the buyers would prefer red
= P(X=9)
= 
=
The number of ways pets can be arranged in group according to the species is in a row 288 ways.
Pets can be grouped by permutation concept as follows.
Total number of pets = 10
Number of dogs = 4
Number of cats = 3
Number of alpacas = 2
Number of bunny = 1
The number of ways pets can be arranged in group according to the species in a row as,
⇒ (4!)(3!)(2!)(1!)
⇒ (24)(6)(2)(1)
⇒ 288
Hence we can conclude that the number of ways pets can be arranged in group according to the species in a row is 288 ways.
Learn more about permutation here
brainly.com/question/22444718
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129/43x100=300
129 is 43% of 300
Here you are. you can see my explication.
have fun