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levacccp [35]
3 years ago
15

A 90 % confidence interval for the average salary of all CEOs in the electronics industry was constructed using the results of a

random survey of 45 CEOs. the interval was ($133, 306, $150, 733). To make useful inferences from the data, it is desired to reduce the width of the confidence interval. Which of the following will result in a reduced interval width?
A) Increase the sample size and increase the confidence level.
B) Decrease the sample size and increase the confidence level.
C) Decrease the sample size and decrease the confidence level.
D) Increase the sample size and decrease the confidence level.
Mathematics
1 answer:
alisha [4.7K]3 years ago
8 0

Answer: D) Increase the sample size and decrease the confidence level.

Step-by-step explanation:

A reduced interval width means that the data is more accurate. This can only be achieved if the sample size is increased because a larger sample size is able to capture more of the characteristics of the variables being tested.

A smaller confidence interval will also lead to a reduced interval width because it means that the chances of the prediction being correct have increased.

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<k=2×15+21=51

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Step-by-step explanation:

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Graph the function for the given domain.<br><br> y = x2 − 4 D:{−2, −1, 0, 1, 2}
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2 years ago
Find x and y <br><br> please help ! tyyyy
garri49 [273]

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Step-by-step explanation:

Since we know that the figure is a right triangle, we can solve for y easily, as 90+y = 180

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so 139+x = 180

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8 0
1 year ago
Given the equation f(x)=2x^2-14x+10, find g(x), the image of f(x) after a ry=x (reflection over the line y=x). Express your answ
Illusion [34]

Given:

The function is:

f(x)=2x^2-14x+10

The function g(x), the image of f(x) after a r_{y=x} (reflection over the line y=x).

To find:

The function g(x).

Solution:

We have,

f(x)=2x^2-14x+10

Substitute f(x)=y in the given function.

y=2x^2-14x+10

The function g(x), the image of f(x) after a r_{y=x} (reflection over the line y=x). So, interchange x and y.

x=2y^2-14y+10

Now, we need to find the value of y.

x=2(y^2-7y+5)

\dfrac{x}{2}=y^2-7y+5             [Divide both sides by 2]

\dfrac{x}{2}-5=y^2-7y             [Subtract 5 from both sides]

Add both sides half of square of coefficient of y, i.e. (\dfrac{-7}{2})^2, to make it perfect square.

\dfrac{x}{2}-5+(\dfrac{-7}{2})^2=y^2-7y+(\dfrac{-7}{2})^2

\dfrac{x}{2}-5+\dfrac{49}{4}=y^2-7y+(\dfrac{7}{2})^2

\dfrac{x}{2}-5+\dfrac{49}{4}=\left(y-\dfrac{7}{2}\right)^2          [\because (a-b)^2=a^2-2ab+b^2]

\dfrac{x}{2}+\dfrac{49-20}{4}=\left(y-\dfrac{7}{2}\right)^2

Taking square root on both sides, we get

\pm\sqrt{\dfrac{x}{2}+\dfrac{29}{4}}=y-\dfrac{7}{2}

\dfrac{7}{2}\pm\sqrt{\dfrac{2x+29}{4}}=y

\dfrac{7}{2}\pm\dfrac{\sqrt{2x+29}}{2}=y

\dfrac{7\pm \sqrt{2x+29}}{2}=y

Substituting y=g(x), we get

\dfrac{7\pm \sqrt{2x+29}}{2}=g(x)

Therefore, the required function is g(x)=\dfrac{7\pm \sqrt{2x+29}}{2}.

6 0
2 years ago
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