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3 years ago

Please help so i can play my electronics

Mathematics

1 answer:

Maslowich3 years ago

8 0

Answer:

All questions are answered in the photo, the answers are correct, but you might have a different method

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Which number has a 3 with a value 1 tenth

butalik [34]

The answer is 13, contains 1 tenth and a 3

7 0

3 years ago

Find the solutions of the form x=a,y=0and x=0 ,y=b for the following equations: 2x+5y=10 and 2x+3y=6. is there any common soluti

Arlecino [84]

Answer:

x=0 and y=2

Step-by-step explanation:

We have been given system of equations:

2x+5y=10 (1)

And 2x+3y=6 (2)

Subtract equation (2) from(1) we get:

2y=4

y=2

Now, substitute y=2 in equation(2) we get:

2x+3(2)=6

2x+6=6

2x=0

x=0

Hence, x=0 and y=2

8 0

3 years ago

Please help guys!! This is kind of hard

murzikaleks [220]

$48
Here's how I found it ( just in case )

4 0

4 years ago

Please help me! I need this answered fast!

Sonja [21]

Answer:

1. I think it's A.

2. I think it's D

8 0

3 years ago

Sqrt(2x-6)=3-x<br> Solve for x

soldi70 [24.7K]

Answer:

x = 3

Step-by-step explanation:

$\sqrt{2x - 6} = 3 - x$

Square both sides of the equation

$2x - 6 = (3 - x)^{2} = 9 - 6x + x^{2} \\$

$x^{2} - 8x + 15 = 0\\$

(x - 3)(x - 5) = 0

x = 3 or 5

Now, you must always check your results because a result may not satisfy the original equation.

If x = 3, then $\sqrt{2x - 6} = \sqrt{2(3) - 6} = \sqrt{6 - 6} = \sqrt{0} = 0$ and 3 - x = 3 - 3 = 0

So 3 satisfies the original.

If x = 5, then $\sqrt{2(5) - 6} = \sqrt{10 - 6} = \sqrt{4} = 2$ , but 3 - x = 3 - 5 = -2. Therefore, 5 does NOT satisfy the original equation.

That means that x = 3 is the solution to the equation.

5 0

3 years ago