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pshichka [43]
2 years ago
12

Anaerobic and aerobic respiration both begin with...

Biology
1 answer:
Zanzabum2 years ago
7 0

Answer:

2. the breakdown of glucose i think...

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Which would provide the body with the most energy?
raketka [301]

Breaking the bonds in a polysaccharide would provide the body with the most energy. Thus, the correct option is D.

<h3>What is Polysaccharide?</h3>

A polysaccharide may be defined as a type of carbohydrate in which molecules are held together by glycosidic bonds. Examples include starch, glycogen, and cellulose.

Breaking such chemical bonds (glycosidic bonds) present in between polysaccharides molecules yield the release of glucose that provide excessive energy for the living organism for metabolism.

Therefore, the correct option for this question is D.

To learn more about Polysaccharides, refer to the link:

brainly.com/question/835889

#SPJ1

5 0
1 year ago
The tracts that connect the cerebellum to the brain stem are located in the
maksim [4K]

Answer:

medulla oblongata.

Explanation:

5 0
3 years ago
The expected ratio of phenotypes among the progeny of a test cross is 1:1:1:1. Out of 200 total resulting progeny, 48 occur in o
Rzqust [24]

Answer: The progeny of this cross do not conform to a 1:1:1:1 ratio

Explanation: This is because out of the 200 total resulting progeny, we must have 50 in each phenotype class to conform with the 1:1:1:1 which is not so as we have 48 in one of the phenotypic class already. Therefore, it did not conform to the ratio.

3 0
3 years ago
A microscope technique that will not allow one to see specific parts of living specimen is
Svetlanka [38]
C using a scanning electron microscope
6 0
3 years ago
In 1980, Y. published an extended pedigree of family in which
nydimaria [60]

Answer:

Zero (0)

Explanation:

According to the given information the genotype of the woman with blood type "AB" would by I^AI^B. The genotype of the man with blood type O would be "ii". Here, the alleles I^A and I^B are dominant over the allele "i".

A cross between parents with genotype I^AI^B and ii would give 50% of children with I^Ai genotype and 50% of children with I^Bi genotype. The children with "I^Ai genotype" would have blood type "A" and the children with I^Bi genotype would have blood type "B". This couple is never likely to have any child with blood type "O" since the mother does not carry allele "i".

Cross: I^AI^B x ii = 1/2 I^Ai : 1/2 I^Bi

5 0
3 years ago
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