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jonny [76]
3 years ago
13

Rename the number to 120,000 ten thousand

Mathematics
1 answer:
Ray Of Light [21]3 years ago
4 0
120,000 renamed to ten thousand (10,000) is twelve ten thousand. Ten thousand in number form is 10,000.  When you divide 120,000 (one hundred and twenty thousand)  by 10,000 (ten thousand) you get 12.  120,000 (one hundred and twenty thousand)  /10,000 (ten thousand) = 12. So there are twelve ten thousands in 120,000.
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(5x+1)(5x-1) combine terms
Alinara [238K]

Answer:

25x^2 -1

Step-by-step explanation:

If you multiply parentheses:

(5x*5x) + (5x*-1) + (1*5x) + (1*-1)

25x^2 - 5x + 5x -1

25x^2 -1

A simpler way is to memorize this formula

(Square1 - square2)= (sqrt of square1- sqrt of square2)*(sqrt of square1 + sqrt of sqaure2)

5 0
3 years ago
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Step-by-step explanation:

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8 0
2 years ago
Question 1
777dan777 [17]

Answer:

There would be 94 tiles.

Step-by-step explanation:

The number of tiles is given by the following equation:

n = 6 + 4p

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This is n when p = 22. So

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2 years ago
4. Write the equation in standard form: y=3/4x – 6
wariber [46]
Y=3x/4-6

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7 0
3 years ago
where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

8 0
3 years ago
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