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3 years ago

3) help I have the answers to these I just need to show the work

Mathematics

1 answer:

vivado [14]3 years ago

8 0

Answer:

will u be my gi rlfriend I love you

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In which graph does y vary directly as x? It’s not C, I got it wrong.

Ludmilka [50]

Hello there!

Based on my research and information, I really believe that (option a) would actually be your correct answer. I believe this basically because sense the letter k is always constant, we would only divide this by what it is, which is y, and from these, your solution would always look like your (option a). Please inform if correct.

Happy to help!

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2 years ago

Triangle A B C. Side A B is 4, B C is 5, A C is 3. Triangle A prime B prime C prime.

madam [21]

Answer:

The correct answer is 15.

Step-by-step explanation:

We are given that the original sides BC is 5. To find the length of B'C' we take the side of BC and multiply it by the scale factor.

5 (original BC) x 5 (the given scale factor) = 15

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2 years ago

Which number replaces h?<br><br><br><br> 14 + 9 = 9 + 8 + h

grin007 [14]

The answer would be 6

4 0

3 years ago

Read 2 more answers

At the city museum, child admission is $6.60 and adult admission is $9.80. On Tuesday, four times as many adult tickets as child

Svet_ta [14]

See photo for solutions

8 0

3 years ago

What is the range of the function y = x 2?

Leno4ka [110]

Answer:

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

Step-by-step explanation:

Given the function

$y=x^2$

We know that the range of a function is the set of values of the dependent variable for which a function is defined.

$\mathrm{For\:a\:parabola}\:ax^2+bx+c\:\mathrm{with\:Vertex}\:\left(x_v,\:y_v\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0\:\mathrm{the\:range\:is}\:f\left(x\right)\ge \:y_v$

$a=1,\:\mathrm{Vertex}\:\left(x_v,\:y_v\right)=\left(0,\:0\right)$

$f\left(x\right)\ge \:0$

Thus,

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

5 0

2 years ago