What is the inverse to 2^x-1

Mathematics

1 answer:

nydimaria [60]3 years ago

4 0

Replace x with y and solve for y~

y=2*

x=2^y

log x = y log 2

y=log x / log 2

Hope this helps and leave a brainliest to help me reach expert ;)

You might be interested in

Answer this. pleaaaaseeee

Evgen [1.6K]

Answer:

look at analysis

Step-by-step explanation:

11. 23.81

12.

part A

y is 12 and x is 4

part B

part C

5×12×4

240

5 0

2 years ago

Provide a clear answer while explaining how to do each step to the question below:

likoan [24]

$\bf ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \sqrt[3]{8x^5y^7} \\\\[-0.35em] ~\dotfill\\\\ \sqrt[3]{8x^5y^7}\implies \sqrt[3]{2^3x^5y^7}\implies \left( 2^3x^5y^7 \right)^{\frac{1}{3}}\implies 2^{3\cdot \frac{1}{3}}x^{5\cdot \frac{1}{3}}y^{7\cdot \frac{1}{3}}\implies 2x^{\frac{5}{3}}y^{\frac{7}{3}}$