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3 years ago

13

Please help me i really need help please please

2 answers:

gizmo_the_mogwai [7]3 years ago

7 0

Answer:

it's D all of the above

Step-by-step explanation:

.......

dsp733 years ago

6 0

The answer is D! Hope you get it right :))

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Which expression is equivalent to 4^ 5x4^ -7÷4 ^-2?

Andre45 [30]

$\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad a^n\implies \cfrac{1}{a^{-n}}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 4^5\cdot 4^{-7}\div 4^{-2}\implies \cfrac{4^5\cdot 4^{-7}}{4^{-2}}\implies \cfrac{4^{5-7}}{4^{-2}}\implies \cfrac{4^{-2}}{4^{-2}}\implies 4^{-2}\cdot 4^2 \\\\\\ 4^{-2+2}\implies \boxed{4^0}\implies 1$

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3 years ago

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Hello! Can some please help me on this problem?

slega [8]

Answer:

It is 1) True hope this helps

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3 years ago

Which of the following equations is the result of completing the square on x^2 - 6x - 9 = 0?

lina2011 [118]

X² - 6x - 9 = 0
x² - 3x - 3x - 9 = 0
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3 years ago

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Does this graph have a maximum<br> or minimum value?

Kazeer [188]

Answer:

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Step-by-step explanation:

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3 years ago

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The graph of f passes through (-6,9) and is perpendicular to the line that has an x-intercept of 8 and a y-intercept of -24 the

Valentin [98]

Given:

The graph of f passes through (-6,9).

It is perpendicular to the line that has an x-intercept of 8 and a y-intercept of -24.

To find:

The equation of the function f.

Solution:

The equation of line on which graph of f is perpendicular, is

$\dfrac{x}{a}+\dfrac{y}{b}=1$

where, a and b are x and y intercepts respectively.

$\dfrac{x}{8}+\dfrac{y}{-24}=1$

Multiply both sides by 24.

$3x-y=24$

Slope intercept form is

$y=3x-24$

Slope of this line is 3 and y-intercept is -24.

Product of slopes of two perpendicular lines is -1.

Let the slope of f is m. So,

$m\times 3=-1$

$m=-\dfrac{1}{3}$

Slope of m is -1/3 and it passes through (-6,9). So, the equation of function f is

$y-y_1=m(x-x_1)$

$y-9=-\dfrac{1}{3}(x-(-6))$

$y-9=-\dfrac{1}{3}(x+6)$

$y-9=-\dfrac{1}{3}x-2$

$y=-\dfrac{1}{3}x-2+9$

$y=-\dfrac{1}{3}x+7$

Put y=f(x).

$f(x)=-\dfrac{1}{3}x+7$

Therefore, the required function is $f(x)=-\dfrac{1}{3}x+7$ .

7 0

3 years ago