Answer:
184 cm²
Step-by-step explanation:
Surface area of the rectangular box is expressed as S = 2(LW+LH+WH)
L is the length of the box = 90 cm
W is the width of the box = 50 cm
H is the height of the box= 90 cm
If there are error of at most 0.2 cm in each measurement, then the total surface area using differential estimate will be expressed as shown;
S = 2{(LdW+WdL) + (LdH+HdL) + (WdH+HdW)
Note that dL = dW = dH = 0.2 cm
Substituting the given values into the formula to estimate the maximum error in calculating the surface area of the box
S = 2{(90(0.2)+50(0.2)) + (90(0.2)+90(0.2)) + (50(0.2)+90(0.2))
S = 2{18+10+18+18+10+18}
S = 2(92)
S = 184 cm²
Hence, the maximum error in calculating the surface area of the box is 184cm²
E^(∞): This is defined as 'e' being raised to a huge value. Hence the result will definitely be a large number which is also infinity (∞), i.e. e^(∞) = ∞.
e^(- ∞) = 1/e^(∞) = 1/∞ = 0.
A) The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle. You know the length of the gift shop, l = 20x + 24. You know the width, w = 36x - 20. Plug those expressions into the equation for area of a rectangle and multiply/foil:
The expression for the area of the gift shop is
.B) The equation for the perimeter of the gift shop is P = 2(l+w), where l = length and w = width. Plug your values for l and w into this equation:
The expression for the perimeter of the gift shop is 112x + 8
C) Since you know the perimeter is going to be 176 ft, that means P = 176. Plug that into the equation you found in part B, P = 112x + 8, and solve for x.

Once you solve for x, you can plug x into your equations for width and length to find the dimensions. x = 1.5, so:
1) L<span>ength = 20x+24 feet
</span>
Length = 20(1.5) + 24 feet =
54 feet
2) Width = <span>36x-20 feet
Width = 36(1.5)-20 feet =
34 feet
Your dimensions are 54 feet (length) by 34 feet (width).</span>
Answer:
Mean and IQR
Step-by-step explanation:
The measure of centre gives the central or the measure which gives the best mid term of a distribution. Based in the details of the box plot, the median is the value which divides the box in the box plot.
For company A:
Range = 25 to 80 with a median value at 30 ; this means the median does not give a good centre measure of the distribution ad it is very close to the minimum value. This goes for the Company B plot too; with values ranging from (35 to 90) and the median designated at 40.
Hence, the mean will be the best measure of centre rather Than the median in this case.
For the variability, the interquartile range would best suit the distribution. With the lower quartile and upper quartile both having reasonable width to the minimum and maximum value of the distribution.
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Answer:
B. infinite set of points on the line
Step-by-step explanation:
The lines are identical, so the set of points they have in common is an ...
infinite set of points on the line