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bagirrra123 [75]
3 years ago
7

Joanne signed up for 24 dancing lessons she took 3/4 of the by April and 1/5 of them by May .What part of dancing lesson did she

take?
Mathematics
1 answer:
gavmur [86]3 years ago
6 0

Answer:

Part = \frac{19}{20}

Lessons = 23

Step-by-step explanation:

Given:

Dancing\ Lessons = 24

April = \frac{3}{4}

May = \frac{1}{5}

Required:

Determine the part she took

To solve this, we simply add up the part she took in April and May.

Part = \frac{3}{4} + \frac{1}{5}

Take LCM

Part = \frac{15 + 4}{20}

Part = \frac{19}{20}

Hence, she took \frac{19}{20} of the dancing lesson.

However, to calculate the number of lesson.

We have to multiply \frac{19}{20} by the total dancing lessons.

Lessons = \frac{19}{20} * 24

Lessons = \frac{19* 24}{20}

Lessons = \frac{456}{20}

Lessons = 22.8

Lessons = 23 ---- Approximated

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The diameter of a circle is calculated by using the formula D=r2pi so plug in the known values to find r=2/pi. Next plug r into the area of a circle formula(A=r^2pi) do so and get 4/pi
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The value of n is...
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Answer:

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Step-by-step-explanation :

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Consider a set of one-dimensional points: 6, 12, 18, 24, 30, 42, 48.
Vinvika [58]

Answer:

1) With initial centroids 10-40, final clusters are

first cluster (6,12,18,24,30)

second cluster (42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 378

2) With initial centroids 10-20, final clusters are

first cluster (6,12,18,24)  

second cluster (30,42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 348

Step-by-step explanation:

K-means works as follows

  • the points will be clustered according to their distance to the centroids.
  • Then centroids are updated as the cluster means.
  • This process continues until clusters doesn't change anymore

1)  <u><em>initial centroids</em></u> 10-40

first cluster (6,12,18,24)  mean:15

second cluster (30,42,48) mean:40

<u><em>new centroids</em></u> 15-40

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

<u><em>final centroids</em></u> 18-45

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

Sum of Squared errors = (18-6)^{2}+(18-12)^{2}+(18-18)^{2}+(18-24)^{2}+(18-30)^{2}+(45-42)^{2}+(45-48)^{2}=378

2)<u><em>initial centroids</em></u> 10-20

first cluster (6,12)  mean:9

second cluster (18,24,30,42,48)  mean:32.4

<u><em>new centroids</em></u> 9-32.4

first cluster (6,12,18) mean:12

second cluster (24,30,42,48) mean:36

<u><em>new centroids</em></u> 12-36

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

<u><em>final centroids</em></u> 15-40

first cluster (6,12,18,24) mean:15  

second cluster (30,42,48) mean:40

Sum of Squared errors = (15-6)^{2}+(15-12)^{2}+(15-18)^{2}+(15-24)^{2}+(40-30)^{2}+(40-42)^{2}+(40-48)^{2}=348

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3 years ago
One fourth the difference of four sixths and three twelfth
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1/4 (4/6 - 3/12) = 1/4 (5/12) = 5/48
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I need help with 25 and 26
valina [46]

25.

The area is b * h, so

(2x + 7) * 4

which is greater than 100 units, so

(2x + 7) * 4 ≥ (don't look at =; only major) 100

8x + 28 ≥ 100

8x ≥ 100 - 28

8x ≥ 72

x ≥ 9

26.

The perimeter is 2 * (b + h), so

2 * (2x + 7 +4) = 2 * (2x + 11)= 4x + 22

which is greater than 50 units, so

4x + 22 ≥ (don't look at =; only major) 50

4x ≥ 50 - 22

4x ≥ 28

x ≥ 7

3 0
3 years ago
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