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2 years ago

I need help with this one plz! (marking BRAINLIST) :)

Mathematics

1 answer:

miskamm [114]2 years ago

3 0

Answer: (a) = 110 degrees, (b) = 8

If I understand the picture correctly, (a) wants you to find the angle K. It first shows us that both J to K, and L to K are equal in length of 11, thus there is no deviation in angle 35 degrees with L (so they both equal each other). Therefore, the angle K will equal 180 degrees subtracted by the sum of J and L, which is 110 degrees.

For (b), it appears that all the angles have the same singular mark at the edges, so all sides will equal 8.

I hope this helped!

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which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

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3 years ago

Which expression best estimates Negative 18 and one-fourth divided by 2 and two-thirds?

Mars2501 [29]

Answer:

-18/3

Step-by-step explanation:

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3 years ago

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Arada [10]

The y intercept of the graphed function and the equation are both -2

(I'm not entirely sure what the question is asking as some of it is blocked out from the drop down box?)

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2 years ago

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LenaWriter [7]

Answer:

x = 60°

Step-by-step explanation:

AOB Center: O AB: diameter

arc ADB = 180°

arc DB = 180 - arc AD = 80°

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2 years ago

What is the next term of the geometric sequence. 135,45,15

WINSTONCH [101]

Answer:

Step-by-step explanation:

Each term is 1/3 of the preceding term

135 / 3 = 45

45 / 3 = 15

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3 years ago

Read 2 more answers

I need help with this one plz! (marking BRAINLIST) :) ​

I need help with this one plz! (marking BRAINLIST) :)