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andrezito [222]
4 years ago
7

(9·20+60)÷4−16+4·(20·5)

Mathematics
2 answers:
neonofarm [45]4 years ago
6 0

\text {Hello! Let's Solve this Problem!}

\text {The First Step is to Solve the Parentheses:}

\text {90*20=180+60=240}\\\text {20*5=100}

\text {Your new Problem should be: 240/4-16+4+100}

\text {The Next Step is to Divide:}

\text {240/4=60}

\text {Your new Problem should be: 60-16+4*100}

\text {The Next Step is to Subtract:}

\text {60-16=44}

\text {Now the Next Step is to Multiply:}

\text {4*100=400}

\text {The Final Step is to Add:}

\text {44+100=}

\text {Your Answer should be:}

\fbox {444}

\text {Best of Luck!}

\text {-LimitedX}

Anon25 [30]4 years ago
6 0

Answer:

444

Step-by-step explanation:

Parentheses

Exponents

Multiplication

or

Division

Addition

or

Subtraction

(9·20+60)÷4−16+4·(20·5) -multiply the first numbers in the first ()

(180+60)÷4−16+4·100 - multiply the numbers in the last ()

240÷4-16+4·100 -add the numbers in the ()

240÷4-16+400 -multiply the last numbers

60-16+400 -divide the firsts numbers

444 -SOLVED

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Please help me find the area of shaded region and step by step​
Bumek [7]

Answer:

Part 1) A=60\ ft^2

Part 2) A=80\ cm^2

Part 3) A=96\ m^2

Part 4) A=144\ cm^2

Part 5) A=9\ m^2

Part 6) A=(49\pi -33)\ in^2

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

A=bh

where

b is the base of rectangle

h is the height of rectangle

so

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A=84-24

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Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

A=b^2

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so

A=(12)(8)-(4^2)

A=96-16

A=80\ cm^2

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

A=4(4)(5)+(4^2)

A=80+16

A=96\ m^2

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

A=(15^2)-(9^2)

A=225-81

A=144\ cm^2

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

A=\frac{1}{2}(b)(h)

where

b is the base of triangle

h is the height of triangle

so

A=\frac{1}{2}(6)(7)-(6)(2)

A=21-12

A=9\ m^2

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

A=\pi r^{2}

where

r is the radius of the circle

so

A=\pi (7^2)-(3)(11)

A=(49\pi -33)\ in^2

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multiply both sides by 2
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