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2 years ago

3(4x - 1) = 5(2x -1)

Mathematics

2 answers:

Sophie [7]2 years ago

8 0

ANSWER

x = -1

x= 1

x = 3

Step-by-step explanation:

the answer is this

dsp732 years ago

3 0

The answer for each of the three questions is provided in the image.
Hope it helped!

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If u(x) = x^5 – x^4 + x^2 and v(x) = –x^2, which expression is equivalent to (u/v)(x)?

Effectus [21]

Hello:
x^5 – x^4 + x^2 =x^2(x^3 - x^2 +1)
(u/v)(x)= x^2(x^3 - x^2 +1)/(-x^2)
(u/v)(x)= - (x^3 - x^2 +1) = -x^3+x^2-1 ( x : no zero)

7 0

3 years ago

one number is equal to two times a second number. two times the first number plus two times the second number is 24. if you let

ziro4ka [17]

X = 2y
2x + 2y = 24
So if x = 2y that means 2x = 4y. Which means that 2x + 2y = 24 can be written as 4y + 2y = 24. Simplified to 6y = 24. Now we need to get 1y so we divide both sides by 6, 6y/6 = y and 24/6 = 4. so y = 4. so x= 2y can be written as x = 8.

5 0

3 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

5 0

3 years ago

What is the solution of the equation x^2 = 64?

timurjin [86]

Answer:

the answer is the First option.

7 0

2 years ago

BRAINLIESTTT ASAP! PLEASE HELP ME :)

sergiy2304 [10]

Answer:

$\displaystyle Maximum: 11$

Step-by-step explanation:

Convert this Quadratic Equation to Vertex Form by completing the square, $\displaystyle y = a[x - h]^2 + k$ :

$\displaystyle -5x^2 -10x + 6 \\ \\ -5x^2 - 10x + 25 + k \\ -5[x^2 + 2x - 5] + k \\ -5[x^2 + 2x + 1] + k → -5[x^2 + 2x + 1] + 11 → f(x) = -5[x + 1]^2 + 11 \\ \\ Vertex: [-1, 11]; 11 = Maximum$

So as you can see, each time we broke the equation down, we used the formula $\displaystyle [\frac{b}{2}]^2$ to complete the square.

** In the Vertex Formula, −h gives the OPPOSITE terms of what they really are, so do not forget it.

I am joyous to assist you anytime.

4 0

2 years ago