Answer:
The amount that I am required to pay monthly as FICA if my salary remains constant is $18,121.85¢
Step-by-step explanation:
Federal insurance contributions act is a law that mandates all employers of labour to withhold medicare and certain taxes from the wages that are paid to employees or workers. These taxes are remitted to the government later which is then used for the provision of basic amenities and quality health care.
Since, I am only required by law to pay FICA on only 92.35% of my monthly salary, we need to calculate the the actual amount that makes up 92.35 percent of my monthly salary.
If $128,255 is my current monthly salary, then 92.35% of it will be:
92.35/100 × 128,255
= 0.9235 × 128,255
= $118,443.49¢
This is the part of his monthly salary that he is required by law to pay FICA on.
Then, if FICA is 15.3% of a worker's taxable income, then I am required to pay 15.3% of the taxable $118,443.49¢ since I am self employed and mustn't pay it on the entire $128,255 that I earn monthly.
My monthly FICA contribution is then:
15.3/100 × 118,443.49
= 0.153 × 118,443.49
= $18,121.85¢.
Therefore, if my salary remains constant, the amount that I am required by law to pay monthly as FICA is $18,121.85
It is best to use mental math with some equations (5x5 or something that is easy enough that work does not have to be shown 10 dived by 5
<span>The length of an arc, L = theta/360 * 2 * pie * r
Where theta = 81 and r = 10ft = 3.048m
So length = 81/360 * 2 * pie * 3.048
L = * 0.225 * 2 * pie * 3.048
L = 1.37 * pie
L = pie. Option A</span>
Answer:
michelle is 23 inches shorter than her dad
Step-by-step explanation:
Answer:
the lower right matrix is the third correct choice
Step-by-step explanation:
Your problem statement shows that you have correctly selected the matrices representing the initial problem setup (middle left) and the problem solution (middle right).
Of the remaining matrices, the upper left is an incorrect setup, and the lower left is an incorrect solution matrix.
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We notice that in the remaining matrices on the right that the (2,3) term is 0, and the (3,2) and (3,3) terms are both 1.
The easiest way to get a 0 in the 3rd column of row 2 is to add the first row to the second. When you do that, you get ...
![\left[\begin{array}{ccc|c}1&1&1&29000\\1+2&1-3&1-1&1000(29+1)\\0&0.15&0.15&2100\end{array}\right] =\left[\begin{array}{ccc|c}1&1&1&29000\\3&-2&0&30000\\0&0.15&0.15&2100\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2629000%5C%5C1%2B2%261-3%261-1%261000%2829%2B1%29%5C%5C0%260.15%260.15%262100%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2629000%5C%5C3%26-2%260%2630000%5C%5C0%260.15%260.15%262100%5Cend%7Barray%7D%5Cright%5D)
Already, we see that the second row matches that in the lower right matrix.
The easiest way to get 1's in the last row is to divide that row by 0.15. When we do that, the (3,4) entry becomes 2100/0.15 = 14000, matching exactly the lower right matrix.
The correct choices here are the two you have selected, and <em>the lower right matrix</em>.
