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lord [1]
3 years ago
14

A survey of a group’s viewing habits over the last year revealed the following

Mathematics
1 answer:
Tom [10]3 years ago
7 0

Answer:

0.52

Step-by-step explanation:

The computation of the percentage of the group in which none of the three sports watched is shown below:

= gymnastic percentage + baseball percentage + soccer percentage - gymnastic & baseball percentage - baseball & soccer percentage - gymnastic & soccer percentage + three sports percentage

= 0.28 + 0.29 + 0.19 - 0.14 - 0.12 - 0.18 + 0.08

= 0.48

Now the percentage is

= 1 - 0.48

= 0.52

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Who knows how to do this ughhh I need help!
suter [353]

Answer:

\large\boxed{\sqrt{56x^{17}}=2x^8\sqrt{14x}}

Step-by-step explanation:

Domain:\ x\geq0\\\\\sqrt{56x^{17}}=\sqrt{4\cdot14\cdot x^{16+1}}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{4\cdot14\cdot x^{16}\cdot x^1}\\\\\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt4\cdot\sqrt{14}\cdot\sqrt{x^{16}}\cdot\sqrt{x}=2\cdot\sqrt{14}\cdot\sqrt{x^{8\cdot2}}\cdot\sqrt{x}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=2\cdot\sqrt{14}\cdot\sqrt{(x^8)^2}\cdot\sqrt{x}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=2\cdot\sqrt{14}\cdot x^8\cdot\sqrt{x}=2x^8\sqrt{14x}

8 0
3 years ago
2x to the second power + 5x + 4​
horrorfan [7]

Answer:

29

Step-by-step explanation:

it might not be right

6 0
3 years ago
What are the solutions to the system <br> y=x^2-6x+7<br> y=-x+13
dolphi86 [110]
I've attached the graphs to this answer. I hope they help. 

3 0
3 years ago
Read 2 more answers
Helpppppppppppppppppp
kakasveta [241]

Answer:

Help with what?

Step-by-step explanation:

I would be happy to answer but you need to attach a question.

5 0
2 years ago
The sum of squares of two consecutive odd numbers is 514 find the numbers ​
amid [387]

Correct Question : The sum of squares of two consecutive positive odd numbers is 514. Find the numbers.

\rule{130}1

Solution :

Let the two consecutive positive odd numbers be x and (x + 2)

\rule{130}1

☯ \underline{\boldsymbol{According\: to \:the\: Question\:now :}}

:\implies\sf x^2 + (x + 2)^{2} = 514 \\\\\\:\implies\sf x^2 + x^2 + 4x + 4 = 514\\\\\\:\implies\sf 2x^2 + 4x + 4 = 514 \\\\\\:\implies\sf 2x^2 + 4x = 514 - 4\\\\\\:\implies\sf 2x^2 + 4x = 510 \\\\\\:\implies\sf 2x^2 + 4x - 510 = 0\\\\\\:\implies\sf x^2 + 2x - 255 = 0 \:\:\:\:\:\Bigg\lgroup \bf{Dividing\:by\:2}\Bigg\rgroup\\\\\\:\implies\sf x^2 + 17x - 15x - 255 = 0\\\\\\:\implies\sf x(x + 17) - 15(x + 17) = 0\\\\\\:\implies\sf (x + 17) (x - 15)\\\\\\:\implies\sf x = - 17\:or\:x = 15\\\\\\:\implies\underline{\boxed {\sf x = 15}}\:\:\:\:\:\Bigg\lgroup \bf{Positive\:odd\: number}\Bigg\rgroup

When,

\bullet\: \textsf {x = } \textbf {15}

\bullet\: \sf x + 2 = 15 + 2 =\textbf{ 17}

\therefore\:\underline{\textsf{The required positive integer is \textbf{15 and 17}}}.

5 0
3 years ago
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