Answer:
Any number which is on left side on the line number is less than the number which is on right hand side relative to that number.
As -28 is on the right hand side of the line number, and -162 is heading towards left hand side relative to -28.
Therefore, -28 is greater than -162.
Step-by-step explanation:
To determine:
Is -28 greater than or less than -162?
Solution Steps:
- In mathematics, a number line is considered to be a straight line with numbers placed at equal intervals along its length.
- A number line could be extended infinitely in any direction i..e -∞ to +∞.
- A number is usually represented horizontally.
Any number which is on left side on the line number is less than the number which is on right hand side relative to that number.
As -28 is on the right hand side of the line number, and -162 is heading towards left hand side relative to -28.
Therefore, -28 is greater than -162.
In other words,

Keywords: number line, less than, greater than
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18=2(5)+b
b=8 y intercept is 8
0=2(x)+8
-8=2x
x=-4
X intercept is -4
Answer:
Step-by-step explanation:
Given


The given system is
can be represented by

The given system is consistent when determinant of A is not equal to zero



i.e. system is consistent for all value of k except 

Answer:
72°
Step-by-step explanation:
From the question,
Area of the circle = πr²
A = πr²................. Equation 1
Where r = radius of the circle.
⇒ r = √(A/π)............. Equation 2
Given: A = 346.5 cm², π = 3.14
r = √(346.5/3.14)
r = √(110.35)
r = 10.5 cm.
Therefore,
circumference of the circle = 2πr = 2×3.14×10.5
circumference = 65.94 m
If the length of the arc(s) is 1/5 of its circumference.
Therefore, length of arc (s) = 13.188
⇒ length of arc/circumference = 13.188/65.94 = 1/5
s/2πr = θ/360
Where θ = angle substends at the center of the circle
1/5 = θ/360
θ = 360/5
θ = 72°
Answer:
Jameel is 13 and Laitfa is 13 x 2 - 10 = 16
16 + 13 = 29
Step-by-step explanation:
The equation has already been given to us, so we just have to solve it.
According to the question,
L + J = 29
L = 2J - 10
L
2J - 10 + J = 29
add 10 both sides
2J + J = 29 + 10 = 39
3J = 39
J = 39/3 = 13
Done!